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3 years ago

Whats the sum and difference of 13-(-17)

Mathematics

1 answer:

ser-zykov [4K]3 years ago

5 0

Sum= positive 30 because you add the opposite
The difference between the numbers is also 30

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Write 10 12/5 as an equivalent improper fraction

romanna [79]

10 $\frac{12}{5}$ = $\frac{(10 X 5 ) + 12}{5}$
= $\frac{62}{5}$

8 0

3 years ago

PLEASE EXPLAIN YOUR ANSWERS!

DedPeter [7]

Answer:

(9 1/2)/(4 3/4)

19/2)/19/4) Divide:

19*4/2*19= 76/38= 2 rooms

Step-by-step explanation:

6 0

3 years ago

Happy Monday Everybody<br><br><br> Free 100 points no joke

alina1380 [7]

Answer:

Happy Monday to you too

Step-by-step explanation:

thx for the point

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3 years ago

Read 2 more answers

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

3 years ago

michael rented a truck for one day. there was a base fee of $20.95 , and there was an additional charge of 93 cents for each mil

jonny [76]

Let x = number of miles, cost per mile = 93 cents = $0.93

Cost = 20.95 + 0.93*x

200.44 = 20.95 + 0.93x

0.93x + 20.95 = 200.44

0.93x = 200.44 - 20.95

0.93x = 179.49

x = 179.49/0.93

x = 193

He drove 193 miles.

6 0

3 years ago