1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BlackZzzverrR [31]
3 years ago
5

Please please Help me

Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0
All you have to do for each question is do (population times growth, the answer of that times 25 plus the original population and that’s 2025 population.
You might be interested in
3x + x + x + x − 3 − 2 = 7 + x + x In the equation above, what is the value of x? A) −5 7 B) 1 C) 12 7 D) 3
oksano4ka [1.4K]

Answer:

x=3

Step-by-step explanation:

3x + x + x + x − 3 − 2 = 7 + x + x

Combine like terms

6x -5 = 7+2x

subtract 2x from each side

6x-2x -5 = 7+2x-2x

4x -5 = 7

Add 5 to each side

4x-5 +5 = 7+5

4x =12

Divide by 4

4x/4 =12/4

x=3

6 0
3 years ago
in parallelogram ABCD, AB=(6x-2) feet DC=(3x+13) feet and AD=5 feet. Find the number of feet in the perimeter of the parallelogr
sweet [91]

Answer:

66 feet

Step-by-step explanation:

Parallelograms have 2 pair of parallel sides that are congruent to each other.

In parallelogram ABCD, we can say:

AB = DC

and

BC = AD

AB and DC are given, and they are equal. So we can say:

AB = DC

6x - 2 = 3x + 13

Now we can solve for x:

6x - 2 = 3x + 13

6x - 3x = 13 + 2

3x = 15

x = 15/3

x = 5

So,

AB = 6x - 2

AB = 6(5) - 2 = 28

So, DC = 28

We are also given AD = 5, so BC = 5 as well [since AD = BC]

Now, we know the length of all 4 sides.

The perimeter is the sum of all 4 sides. Hence,

Perimeter = 28 + 28 + 5 + 5 = 66 feet

6 0
4 years ago
Ok y’all i need to know something.
just olya [345]

Answer:

yea ask your teacher or just do it to look as a better student

8 0
3 years ago
The illuminance of a surface varies inversely with the square of its distance from the light source. If the illuminance of a sur
lesya692 [45]

Answer: b) 6

Step-by-step explanation:

Given : The illuminance of a surface varies inversely with the square of its distance from the light source.

i.e. for d distance and l luminance , we have

d^2\times l=k , where k is constant.       (1)

If  the illuminance of a surface is 120 lumens per square meter when its distance from a certain light source is 6 meters.

From (1), we have

\Rightarrow (6)^2\times 120=k\\\\\Rightarrow\ k=4320   (2)

For the distance (d) corresponds to the illuminance to 30 lumens per square meter , we have

d^2\times 30=k

Put value of k , we get

d^2\times 30=4320\\\\\Rightarrow\ d^2=\dfrac{4320}{30}=144\\\\\Rightarrow\ d^2=144\\\\\Rightarrow\ d= 12

Then , the number of meters should the distance of the surface from the source be increased= 12 meters- 6 meters = 6 meters.

3 0
3 years ago
8 x 1,000,000+5 x 10,000+2 x 1,000+6 x 100 in standard form?
SpyIntel [72]

Answer:

8052600

Step-by-step explanation:

According to the Order of Operations, in this case, you deal with all multiplication before adding everything up.

I am joyous to assist you anytime.

3 0
3 years ago
Other questions:
  • PLEASE HELP!! WILL GIVE BRAINLIEST!!
    12·1 answer
  • What integer is the opposite of –7?(a)1/7 (b)7 (c)-7 (d)-1/7
    9·1 answer
  • Question #9*
    7·1 answer
  • What is -15.41 round to the nearest hundredth
    12·1 answer
  • Use the figure above to answer the questions.
    11·1 answer
  • What is the difference between a sequence and a series? What is the difference between a geometric and an arithmetic sequence?
    15·1 answer
  • Which ratio does not belong with the other three? Explain your reasoning. 4/10 2/5 3/5 6/15
    7·1 answer
  • X - 3.5 = -3.1<br> solve for x.
    9·2 answers
  • PLEASE SOMEONE WOULD THEY TELL ME PLEAsee?!!!
    6·2 answers
  • For the week , emma had originally selected 8 intervals the interval she put up was not picked up or swapped , nor did she show
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!