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nordsb [41]
3 years ago
14

in parallelogram ABCD, AB=(6x-2) feet DC=(3x+13) feet and AD=5 feet. Find the number of feet in the perimeter of the parallelogr

am
Mathematics
1 answer:
sweet [91]3 years ago
6 0

Answer:

66 feet

Step-by-step explanation:

Parallelograms have 2 pair of parallel sides that are congruent to each other.

In parallelogram ABCD, we can say:

AB = DC

and

BC = AD

AB and DC are given, and they are equal. So we can say:

AB = DC

6x - 2 = 3x + 13

Now we can solve for x:

6x - 2 = 3x + 13

6x - 3x = 13 + 2

3x = 15

x = 15/3

x = 5

So,

AB = 6x - 2

AB = 6(5) - 2 = 28

So, DC = 28

We are also given AD = 5, so BC = 5 as well [since AD = BC]

Now, we know the length of all 4 sides.

The perimeter is the sum of all 4 sides. Hence,

Perimeter = 28 + 28 + 5 + 5 = 66 feet

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For this case we have an equation with a variable of the form y = h (x). Where h (x) = 3x-19. Given the value ofh (x) = 71, we want to find the value of the variable "x". So, we have:

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