In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution
We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ + v₂c₂
40(0.32) = 10(0.2) + 30c
Answer:
2x+3y+32
Step-by-step explanation:
Answer:
(1-2b)/126b^2
Step-by-step explanation:
(7b-14b^2)/(42b^2*21b)
factor out the 7b,
[7b(1-2b)]/882b^3
[7b(1-2b)]/[7b(126b^2)]
cancel out the 7b's
(1-2b)/126b^2
Last one should be less than 3/4
