Answer:
Explanation:
Given that,
A capacitor of capacitance
C = 500pF
Charge on capacitor is
Q = 10μC
Capacitor is then connected to an inductor of inductance 10H
L = 10H
Since we want to calculate the maximum energy stored by the inductor, then, we will assume all the energy from the capacitor is transfer to the inductor
So energy stored in capacitor can be determined by using
U = ½CV²
Then, Q = CV
Therefore V = Q/C
U = ½ C • (Q/C)² = ½ C × Q²/C²
U = ½Q² / C
Then,
U = ½ × (10 × 10^-6)² / (500 × 10^-9)
U = 1 × 10^-4 J
U = 0.1 mJ
So the energy stored in this capacitor is transfers to the inductor.
So, energy stored in the inductor is 0.1mJ
B. Current through the inductor
Energy in the inductor is given as
U = ½Li²
1 × 10^-4 = ½ × 10 × i²
1 × 10^-4 = 5× i²
i² = 1 × 10^-4 / 5
i² = 2 × 10^-5
I = √(2×10^-5)
I = 4.47 × 10^-3 Amps
Then,
I = 4.47 mA
The speed of the runner is 300 m /38 seconds. You can simplify this answer to be about 7.9 m/s
Answer:
im not too sure about that all i know is history
Answer:
Maximum acceleration will be equal to 
Explanation:
We have given coefficient of kinetic friction 
And coefficient of static friction 
Acceleration due to gravity 
When truck moves maximum force will be equal to 
It is given that half of the weight is supported by its drive wheels
So force required 
From newtons law maximum acceleration will be equal to 
I believe the answer would be Kinetic Energy. Kinetic energy is defined as energy which a body possesses by virtue of being in motion. We weren’t given answer choices so I don’t have much to work with lol.
