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hammer [34]
3 years ago
7

Now in "real life," this automobile is cruising at 20.5 m/s (equal to 73.8 km/hr) when it is about to hit a pedestrian stuck in

the middle of the road. The super hero Mr. Incredible comes to the rescue. He does not want to get sued, however. Therefore, he will not push the car with a force greater than 2.0 ✕ 104 N; otherwise, the bumper will get damaged. How much time (in s) does he need to stop this car?
Physics
1 answer:
algol133 years ago
5 0

Answer:

He needs 1.53 seconds to stop the car.

Explanation:

Let the mass of the car is 1500 kg

Speed of the car, v = 20.5 m/s

He will not push the car with a force greater than, F=2\times 10^4\ N

The impulse delivered to the object is given by the change in momentum as :

F\times t=mv\\\\t=\dfrac{mv}{F}\\\\t=\dfrac{1500\times 20.5}{2\times 10^4}\\\\t=1.53\ s

So, he needs 1.53 seconds to stop the car. Hence, this is the required solution.

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In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80m/
polet [3.4K]
V o - initial velocity
v = velocity at the maximum height,
v² = v o² - 2 g h
v = 0
0 = v o² - 2 g h
v o² = 2 g h = 2 · 9.80 · 0.460
v o² = 9.052
v o = √9.052 = 3.004197 m/s ≈ 3 m/s
8 0
3 years ago
A billion years ago, Earth and its moon were just 200000 kilometers apart. Express this distance in meters.​
Luda [366]

Answer:

The  value is  x =  200000000 \  m

Explanation:

From the question we are told that

  The  distance between the earth and the moon is  d  =  200000 \  km

Generally ,

     1 \  km  =  1000 \  m

      200000 \  km \to x \  m

=>    x = \frac{200000 *  1000}{1 }

=>   x =  200000000 \  m

           

4 0
2 years ago
The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5
nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

G\frac{mM}{R^2}=m\frac{v^2}{R}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

m=11,100 kg is the mass of the telescope

M=5.97\cdot 10^{24} kg is the mass of the Earth

R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s

6 0
3 years ago
IF YOU MOVE 50 METERS IN TO SECONDS,
Yanka [14]
You can use photo math for This
5 0
2 years ago
Describe the difference between particle motion in solids and liquids.
4vir4ik [10]

Answer:

Particles in a: gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

i hope this helps your answer

5 0
3 years ago
Read 2 more answers
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