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GuDViN [60]
3 years ago
11

The moon's gravitational pull causes _____.

Physics
2 answers:
Hunter-Best [27]3 years ago
8 0
<span>The moon's gravitational pull causes: currents tides.</span>
riadik2000 [5.3K]3 years ago
3 0
<h3><u>Answer;</u></h3>

Tides

<h3><u>Explanation;</u></h3>
  • <em>The moon's gravitational pull causes ocean tides. Gravity is one main force that causes ocean tides. </em>
  • <em><u>Ocean tides results from the gravitational attraction of the moon and the sun on the oceans on the earth's surface. </u></em>
  • <em><u>Gravitational attraction of the sun and the moon causes the water in the oceans to bulge, and thus resulting to a continuous change between high and low tide.</u></em> Spring tides for instance are created at new moon and full moon when the gravitational force of moon  and that of the sun act together.

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Bethany feels as though she cannot enjoy flowers properly, as she has lost her sense of smell. Bethany has _______
Zolol [24]

Answer: Anthophobia

Explanation: A fear of flowers

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3 years ago
Can you guys please help me on this one?​
LenKa [72]

If the object is not at rest how?

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2 years ago
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A team of engineering students is designing a catapult to launch a small ball at A so that it lands in the box. If it is known t
Murljashka [212]

Answer:

Explanation:

If the initial velocity is U

Then the horizontal component of the velocity is

Ux= Ucosθ

Then the range for a projectile is give as

R=Ux.t

Where t is the time of flight

The time of flight is given as

t=2USinθ/g

Therefore,

R=Ux.t

R=UCosθ.2USinθ/g

R=U^2×2SinθCosθ/g

Then, from trigonometric ratio

2SinθCosθ= Sin2θ

R=U^2Sin2θ/g

Given that θ=32° and g=9.81m/s^2

Then

R=U^2Sin2×32/9.81

R=U^2Sin64/9.81

R=0.0916U^2

Then, range is given by R=0.0916U^2

A=0.0916U^2.

T

The box is at a distance A from the point of projection. Then the range R=A

R=0.0916U^2

A=0.0916U^2

Then,

U^2=A/0.0916

U^2=10.915A

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8 0
4 years ago
Which technology contains at least one permanent magnet?
stich3 [128]
I’m pretty sure it’s, B. An Electric Motor. I apologize in advance if it’s incorrect.
6 0
3 years ago
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After a plant or animal dies the 14C content decreases with a half-life of 5730 years. If an archaeologist finds an ancient fire
Shalnov [3]

Answer:

age of the site is 15411.75 years old

Explanation:

Given data

plant or animal dies = 14C

time period = 5730 year

carbon = 15.5%

to find out

age (in years) of the ancient site

solution

we know that Final value = Initial value  × 0.5^{n}

here n is half life passed

so for 15.5%

15.5% = 100% of  0.5^{n}

0.155 = 1 × 0.5^{n}

now take log both side

log 0.155 = log  0.5^{n}

n = log 0.155 / log 0.5

n = 2.68966

we know here  5730 years in half life

so for 2.68966 half-lives = 2.68966 × 5730  =  15411.7518

age of the site is 15411.75 years old

6 0
3 years ago
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