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Ivanshal [37]
3 years ago
15

Suppose you were starting in the office cleaning service. We have spent $315 on equipment. To clean an office, you use four doll

ars worth of supplies. You charge $25 per office. How many officers must clean to break even?
Mathematics
1 answer:
zzz [600]3 years ago
4 0

Answer:

Number of offices to be cleaned to cover the cost of equipment =15

Cost of equipment =$.315 Cost of supplies =$.4 Charge per office =$.25

Number of offices to be cleaned to cover the cost of equipment =x

Then -25x − 4x =315

21x =315

x=315

21=15

Number of offices to be cleaned to cover the cost of equipment =15

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Suppose that in one region of the country the mean amount of credit card debt perhousehold in households having credit card debt
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Answer:

The probability that the mean amount of credit card debt in a sample of 1600 such households will be within $300 of the population mean is roughly 0.907 = 90.7%.

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To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 15250, \sigma = 7125, n = 1600, s = \frac{7125}{\sqrt{1600}} = 178.125

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This probability is the pvalue of Z when X = 1600 + 300 = 1900 subtracted by the pvalue of Z when X = 1600 - 300 = 1300. So

X = 1900

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1900 - 1600}{178.125}

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Z = 1.68 has a pvalue of 0.9535.

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Z = \frac{X - \mu}{s}

Z = \frac{1300 - 1600}{178.125}

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Z = -1.68 has a pvalue of 0.0465.

0.9535 - 0.0465 = 0.907.

The probability that the mean amount of credit card debt in a sample of 1600 such households will be within $300 of the population mean is roughly 0.907 = 90.7%.

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