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grin007 [14]
3 years ago
10

How many students were enrolled by the end of the fourteenth century at the university of salamanca?

Mathematics
1 answer:
zmey [24]3 years ago
5 0
There were about 500 to 600 students that attended the University of salamanca by the end of the 14th century
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How do you find the percent error?
natita [175]
(Observed data - Accepted standard) divided by the accepted standard. Then all of that is multiplied by 100.

( ( O - A ) / A) * 100
6 0
3 years ago
I don't know how to solve this
sergiy2304 [10]
The answer that I got was side  WX = 12 inches

It says that WY is congruent to XY which means that they are the same. That means that XY is also 3m-4. It also says that the perimeter of the triangle is 76 inches.

With this information I set up an equation:

3m-4 + 3m-4 +m = 76

(The number on the right side is the perimeter given to us in the problem and the numbers on the left side are the 3 side lengths).

I combined like terms on the left side and ended up with:

7m-8=76 

I added 8 to both sides of the equation and got 7m=84.

Finally I divided both sides by 7 and got m=12

m is equivalent to side WX..

Hope this helps!
4 0
3 years ago
HELP PLEASE THANKS!!!!!
STALIN [3.7K]
Multiply 11 yards by 7 yeards and you will get ur answrr
4 0
2 years ago
The volume of a sphere is 2254 pi m^3 what is the surface area of the sphere to the nearest 10th
Advocard [28]
By definition. The volume of the sphere is:
 V = (4/3) * (pi) * (r ^ 3)
 Where,
 r: radius of the sphere.
 Substituting values:
 2254 pi = (4/3) * (pi) * (r ^ 3)
 Clearing the radio we have:
 r ^ 3 = (3/4) * (2254)
 r = ((3/4) * (2254)) ^ (1/3)
 r = 11.91255883
 Then, the surface area is:
 A = 2 * pi * r ^ 2
 Substituting values:
 A = 2 * 3.14 * (11.91255883) ^ 2
 A = 891.6 m ^ 2
 Answer:
 
The surface area of the sphere is:
 
b. 891.6 m ^ 2
8 0
3 years ago
Find the surface area of this composite solid.
babunello [35]
Not sure but a guess that the answer is
C. 84 m^2
8 0
4 years ago
Read 2 more answers
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