Each are non-metals, which form a covalent bond. They also have high electron rapport.
- nonmetal and nonmetal equals covalent bond.
Answer:
32/21
Explanation:
Find the GCD (or HCF) of numerator and denominator. GCD of 32 and 21 is 1.
32 ÷ 121 ÷ 1.
Reduced fraction: 3221. Therefore, 32/21 simplified to lowest terms is 32/21.
<u>Answer:</u> The molar solubility of MX is 
<u>Explanation:</u>
We are given:
The chemical equation for the ionization of MX follows:
S S
The expression of 
for above equation is:
......(1)
The chemical equation for the ionization of 
follows:
0.25M 0.5M 0.25M
Total concentration of cation from both the equation is:
![[M^+]=0.5+S](https://tex.z-dn.net/?f=%5BM%5E%2B%5D%3D0.5%2BS)
As, 
, so S is also very very less than 1 and can be easily neglected.
So, ![[M^+]=0.5M](https://tex.z-dn.net/?f=%5BM%5E%2B%5D%3D0.5M)
Putting values in equation 1, we get:
Hence, the molar solubility of MX is
The answer is the upper right Fluorine is the most electronegative.
Answer:
Before you use log you have to multiply the answer of 8.66 mol by 6.02⋅1023 by 3 because the answer of 8.66 mol by 6.02⋅1023 gives you the number of ammonia molecules and in each molecules there are 3 hydrogen atoms present.
Explanation:
