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Alika [10]
3 years ago
15

URGENT - This is not really specific but I have a chemistry test really soon and I still don't understand how to balance chemica

l equations.. I've watched every video and tried practicing but I just still can't understand. Can someone help, please? 30 points will be given out + a brainliest answer will be picked
Chemistry
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

Explanation:

- the key thing to note is that balancing is simply having equal amounts of all the compounds in an equation

1) look at how many there are in each compound i.e. cl2 has 2 and HCl has 1 hydrogen and 1 chlorine

2) balance the reactants with its products

this is done by adding a number in front of a compound

e.g. ch4 + cl2 = ccl4 + hcl

balanced: ch4 + 4cl2 = ccl4 + 4hcl

this is because there isnt equal elements of the compounds

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4 0
3 years ago
What is the boiling point of a solution produced by adding 610 g of cane sugar (molar mass 342.3 g/mol) to 1.4 kg of water? For
wel

Answer:

Boiling point of solution is 100.65^{0}\textrm{C}

Explanation:

Cane sugar is a non-volatile solute.

According to Raoult's law for a non-volatile solute dissolved in a solution-

                              \Delta T_{b}=K_{b}.m

Where, \Delta T_{b} is elivation in boiling point of solution, K_{b} is ebbulioscopic constant of solvent (how much temperature is raised for dissolution of 1 mol of non-volatile solute) and m is molality of solution.

Here, K_{b}=0.51^{0}\textrm{C}.kg.mol^{-1}

610 g of cane sugar = \frac{610}{342.3} moles of cane sugar

                                  = 1.78 moles of cane sugar

So, molality of solution (m) = \frac{1.78}{1.4}mol.kg^{-1}=1.27mol.kg^{-1}

Plug in all the values in the above equation, we get-

\Delta T_{b}=0.51^{0}\textrm{C}.kg.mol^{-1}\times 1.27mol.kg^{-1}=0.65^{0}\textrm{C}

So, boiling point of solution = (100+0.65)^{0}\textrm{C}=100.65^{0}\textrm{C}              

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3 years ago
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7 0
3 years ago
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Answer:

When a Magnesium Ribbon is burnt, a powdery substance called magnesium oxide is formed.

Explanation:

There has obviously been a chemical change because several chemical properties of the magnesium have been modified:  the color, the texture and the mass.

The increase in mass is due to the fact that oxygen from the air has combined with the magnesium to make magnesium oxide, MgO.

The chemical equation, Mg + O2  MgO shows this reaction but it needs to be balanced to make 2Mg + O2  2MgO.  

Using stoichiometry, we can convert this eqation into an equation with moles:  

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Lastly, we determine the same thing in the proportions we used.  In other words, we used only 0.15g of Mg (not 48g) so everything needs to be divided by 320.  So 80 / 320 = 0.25 g.  If we burn 0.15 g of Mg, we obtain 0.25 g of MgO.

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Answer:

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