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Alika [10]
2 years ago
15

URGENT - This is not really specific but I have a chemistry test really soon and I still don't understand how to balance chemica

l equations.. I've watched every video and tried practicing but I just still can't understand. Can someone help, please? 30 points will be given out + a brainliest answer will be picked
Chemistry
1 answer:
UkoKoshka [18]2 years ago
8 0

Answer:

Explanation:

- the key thing to note is that balancing is simply having equal amounts of all the compounds in an equation

1) look at how many there are in each compound i.e. cl2 has 2 and HCl has 1 hydrogen and 1 chlorine

2) balance the reactants with its products

this is done by adding a number in front of a compound

e.g. ch4 + cl2 = ccl4 + hcl

balanced: ch4 + 4cl2 = ccl4 + 4hcl

this is because there isnt equal elements of the compounds

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Answer: Look it up on the internet

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3 years ago
Lead will float in water.
Fed [463]

Actually, no. While their mass may be the same (1kg), the volume of lead is a lot smaller than that of feathers. As there is the same mass stuffed in a smaller space, it must be denser. The density of water is 1 g/cm3, so if the density of the lead is more than 1g/cm3, it has to sink

7 0
3 years ago
Read 2 more answers
In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol). Calculate the number of moles of chl
Annette [7]

Answer:

3.67 mol Cl

Explanation:

We need to convert g of Cl 2 to moles of Cl. First we divide 130 gCl2  by the molar mass (70.90 gCl2/mol) to find out how many moles of Cl2 do we have.

130 gCl2 x \frac{1 mol Cl2 }{70.90 gCl2} = 1.83 mol Cl2

Then we need to convert 1.83 mol de Cl2 to moles of Cl. We have 2 moles of Cl in every Cl2 molecule so we just need to multiply by 2.

1.83 molCl2 x \frac{2 molCl}{1 molCl2} = 3.67 molCl

8 0
3 years ago
Read 2 more answers
1. How many molecules of S2 gas are in 756.2 L?
AfilCa [17]

Answer: There are 2.032 \times 10^{25} molecules S_{2} gas are in 756.2 L.

Explanation:

It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of  moles present in 756.2 L are calculated as follows.

Mole = \frac{Volume}{22.4 L}\\= \frac{756.2 L}{22.4 L}\\= 33.76 mol

According to mole concept, 1 mole of every substance contains 6.022 \times 10^{23} molecules.

Therefore, molecules of S present in 33.76 moles are calculated as follows.

1 mol = 6.022 \times 10^{23}\\33.76 mol = 33.76 \times 6.022 \times 10^{23}\\= 2.032 \times 10^{25}

Thus, we can conclude that there are 2.032 \times 10^{25} molecules S_{2} gas are in 756.2 L.

5 0
3 years ago
Which of the following equations does not demonstrate the law of conservation of mass?
enot [183]

The third option does not obey the law of conservation of mass.

Option 3.

Explanation:

The law of conservation of mass states that the sum of the masses of reactants should be equal to the sum of the masses of the products.

For example, if we consider the first option to verify if it obeys law of conservation of mass or not, 2 Na + Cl₂ → 2 NaCl

So one way to verify it is to find the mass of Na, then multiply it with 2, and then add this with 2 times of mass of chlorine. So this sum should be equal to the 2 times mass of NaCl. But it is somewhat lengthy.

Another way to easily determine this is to check if the elements are present equally in both sides. Such as, in reactant side and product side 2 atoms of Na is present . Similarly, the Cl atoms are also present in equal number in both reactant and product side. Thus this obeyed the law of conservation of mass.

Like this, if we see the second option, there also 1 atom of Na is present in reactant and product side and 2 molecules of H is present in reactant and product side, 1 oxygen is present in reactant and product side and 1 Cl is present in reactant and product side. So it also obeys the law of conservation of mass.

But in the third option, P₄ + 5 O₂→ 2 P₄O₁₀, here, there is 4 atoms of P in reactant side but in product side there is (4*2) = 8 atoms of P. Similarly, the number of atoms of oxygen in reactants and product side is also not same. So the third option does not obey the law of conservation of mass.

The fourth option also obeys the law of conservation of mass as the number of atoms of each element is same in both the product and reactant side.

Thus, the third option does not obey the law of conservation of mass.

5 0
3 years ago
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