Answer:
12 moles of propane.
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 216 L
Pressure (P) = 184.8 KPa
Temperature (T) = 127 °C
Number of mole (n) =?
Next, we shall convert 127 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 127 °C
T(K) = 127 + 273
T(K) = 400 K
Finally, we shall determine the number of mole of propane gas in the container. This can be obtained as follow:
Volume (V) = 216 L
Pressure (P) = 184.8 KPa
Temperature (T) = 400 K
Gas constant (R) = 8.314 L.KPa/Kmol
Number of mole (n) =?
PV = nRT
184.8 × 216 = n × 8.314 × 400
39916.8 = n × 3325.6
Divide both side by 3325.6
n = 39916.8 / 3325.6
n = 12 moles
Thus, 12 moles of propane is present in the cylinder
Answer:
4
Explanation:
4.They are different states of the same pure substance
16287.50 I think? I just googled it though so I’m not sure if it’s correct.
Answer: The final concentration of 
at equilibrium is 0.36 M
Explanation:
Moles of 
= 0.64 mole
Volume of solution = 1.0 L
Initial concentration of = 
The given balanced equilibrium reaction is,
Initial conc. 0.64 M 0M 0M
At eqm. conc. (0.64-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCl_2%5D%5Ctimes%20%5BPCl_3%5D%7D%7B%5BPCl_5%5D%7D)
Now put all the given values in this expression, we get
By solving the term 'x', we get :
x = 0.36
Thus, the final concentration of at equilibrium is x = 0.36 M
