I'm going to use m for minutes
Cell carrier 1
0.15 per minute (0.15m)
$26.50 first, and then add on for every minute
cost carrier 1 = 0.15m + 26.50
carrier 2
0.25 per minute (0.25m)
$14.50 first, and then add on for every minute.
cost carrier 2 = 0.25m + 14.50
to find out when they cost the same, make the two costs equal to each other:
0.15m + 26.50 = 0.25m + 14.50
all that's left is to solve for m
0.15m + 26.50 = 0.25m + 14.50
subtract both sides by 0.15 m
26.50 = 0.2m + 14.50
subtract both sides by 14.50
12 = 0.1 m
divide both sides by 0.1
m = 120
the phone carriers will have the same cost at 120 minutes
Answer:
It would be 14 because since each book is 3.5cm thick times that by 4 and get 14.
Solve for w
divide each side by factors that don’t contain the variable
w = 14
<span>Let p be the probability that an adult was never in a museum. Hence p = 0.15. Then q is the probability that an adult was in a museum is 1 - 0.15 = 0.75. We have a binomial expansion where the probability of k success in n trials is given by
P_n(k) = (n, k) p^(k) q^(n -k) where (n, k) is the number of ways to select 10 objects from k things.
At least two or fewer means we have P_10 (< or equal to 2)
So we have P_10 (less than or equal to 2) = P_10 ( 0) + P_10 (1) + P_10 (2).
So we have P _10 (0) = ( 10, 0) (0.15)^ (0) (0.75)^(0) = 0.196. For P_10(1), we have 0.3474 and for P_10(2), we have 0.2758. Adding these we have 0.1960 + 0.3474 + 0.2758 = 0.8192.</span>
49x^2 - 9 = 0
As there is no x term, we can pretty much guess we have a situation where we factlrise by something known aa difference of two squares, so to factorise it:
49 = 7^2
9 = 3^2
x^2 = (x)^2
so...
(7x - 3)(7x + 3) = 0
7x - 3 = 0 7x + 3 = 0
x = 3/7 x = -3/7
