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densk [106]
3 years ago
13

Imagine that you run this experiment and that the initial change in pressure is 0.0023 atm/s. what is the initial reaction rate?

the temperature of the water bath is 20.0 oc.
Chemistry
1 answer:
svet-max [94.6K]3 years ago
6 0

\text{reaction rate} = 9.6 \times 10^{-5} \; \text{mol}\cdot\text{L}^{-1} \cdot \text{s}^{-1}

Explanation:

Concentration c = n / V;

The reaction see a 0.0023 \; \text{atm} change in pressure per second. By the ideal gas law, this quantity would correspond to a change in concentration, n/V of

c = n / V = P / (n \cdot R) = 0.0023 / ((273.15 + 20) \times 0.0821 ) = 9.6 \times 10^{-5} \; \text{mol}

where the ideal gas constant R = 0.0821 \; \text{L} \cdot \text{atm} \cdot \text{mol}^{-1} \cdot \text{K}^{-1}.

By definition, \text{reaction rate} = \Delta \text{concentration} / \Delta\text{time}

Therefore, for this particular reaction

\text{rate} = 9.6 \times 10^{-5} \; \text{mol} / (1 \; \text{s} ) = 9.6 \times 10^{-5} \; \text{mol}  \cdot \text{L}^{-1} \cdot \text{s}^{-1}

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