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Yakvenalex [24]
3 years ago
13

Commercial cold packs often contain solid NH4NO3 and a pouch of water. The temperature of the pack drops as the NH4NO3 dissolves

in water. Therefore, for the dissolving of NH4NO3 in water, a. ΔHsoln is positive and ΔSsoln may be negative or positive. b. ΔHsoln is positive and ΔSsoln is positive. c. ΔHsoln is negative and ΔSsoln is positive. d. ΔHsoln is negative and ΔSsoln may be negative or positive.
Chemistry
1 answer:
Yanka [14]3 years ago
7 0

Answer: b. \Delta H_{soln} is positive and \Delta S_{soln} is positive.

Explanation:-

As the temperature of the pack drops, the energy has been absorbed from the pack for dissolution of NH_4NO_3 in water. Thus as the energy has been absorbed in the reaction, the reaction is endothermic and the change in enthalpy i.e. \Delta H_{soln} is positive.

The entropy is the measure of degree of randomness. The entropy increases when the randomness increases and the entropy decreases when the randomness decreases. When a substance dissolves in water, it dissociate into ions and hence the randomness increases thus the change in entropy i.e. \Delta S_{soln}  is positive.

NH_4NO_3\rightarrow NH_4^++NO_3^-

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The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M


calculation


concentration = moles /volume in liters


volume in liters = 150 /1000= 0.15 L


number of moles calculation

write the equation for dissociation of Al2Cl3

that is AlCl3 ⇔ Al^3+ + 3 Cl ^-


find the moles of Cl^- formed

moles =mass/molar mass

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molar mass of Cl^- =35.5 g/mol


moles is therefore= 0.55/35.5 =0.0155 moles


by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles



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A neutral atom posseses an atomic number of 15 and an atomic mass of 31 3 electrons are gained
kodGreya [7K]

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Answer:

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