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Yakvenalex [24]
2 years ago
13

Commercial cold packs often contain solid NH4NO3 and a pouch of water. The temperature of the pack drops as the NH4NO3 dissolves

in water. Therefore, for the dissolving of NH4NO3 in water, a. ΔHsoln is positive and ΔSsoln may be negative or positive. b. ΔHsoln is positive and ΔSsoln is positive. c. ΔHsoln is negative and ΔSsoln is positive. d. ΔHsoln is negative and ΔSsoln may be negative or positive.
Chemistry
1 answer:
Yanka [14]2 years ago
7 0

Answer: b. \Delta H_{soln} is positive and \Delta S_{soln} is positive.

Explanation:-

As the temperature of the pack drops, the energy has been absorbed from the pack for dissolution of NH_4NO_3 in water. Thus as the energy has been absorbed in the reaction, the reaction is endothermic and the change in enthalpy i.e. \Delta H_{soln} is positive.

The entropy is the measure of degree of randomness. The entropy increases when the randomness increases and the entropy decreases when the randomness decreases. When a substance dissolves in water, it dissociate into ions and hence the randomness increases thus the change in entropy i.e. \Delta S_{soln}  is positive.

NH_4NO_3\rightarrow NH_4^++NO_3^-

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bekas [8.4K]
Answer is: 1,92 mol/L·s.
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8 0
3 years ago
If a gas in a closed container is pressurized from 15.0 atmospheres to 16.0
Yuki888 [10]

Answer:

T₂ = 317.87 K

Explanation:

Given data:

Initial pressure = 15 atm

Final pressure = 16 atm

Initial temperature = 298 K

Final temperature = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

15 atm / 298K = 16 atm/T₂

T₂ = 16atm × 298 K / 15 atm

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4 0
3 years ago
Consider the reaction ch3oh(l)→ch4(g)+1/2o2(g). part a calculate δrh∘298.
Vsevolod [243]
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ΔHrxn° = ∑(ν×ΔHf° of products) - ∑(ν×ΔHf° of reactants)
where
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The ΔHf° for the substances are the following:
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8 0
2 years ago
Read 2 more answers
A student puts 0.020 mol of methyl methanoate into an empty and rigid 1.0 L vessel at 450 K. The pressure is measured to be 0.74
stellarik [79]

Explanation:

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At the equilibrium 50 % of the ethanol acid molecules reacted

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Moles of the product (CH3COOH)^{2} gas formed are calculated as

0.010 mol CH3COOH * 1 mol (CH3COOH)^{2} / 2 mol CH3COOH

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Now Calculate the pressure  :

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4 0
3 years ago
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Masja [62]

Answer:

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Explanation:

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Considering the original question was in the context of chemistry, I wanted to make it seem formal and more educational too. Hopefully that worked!  

EDIT: Came up with some text around what happens inside cells that would have made it better if someone just had an issue converting units, but I doubt my answer will be accepted >.<

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