Question

An ideal Carnot engine extracts of heat from a high-temperature reservoir at 1200 during each cycle, and rejects heat to a low-temperature reservoir at 700K during the cycle. What is the efficiency of the engine

Answer 1

Answer:

efficiency of the engine is 0.4167

Explanation:

given data

T high = 1200 K

T low = 700 K

solution

we get here efficiency that is express as

efficiency  = $1 - \frac{T\ low}{T \ high }$    .........................1

put here value of both temperature we get efficiency  

efficiency  = 1 - $\frac{700}{1200}$

efficiency  = 1 - 0.58333

efficiency  = 0.4167

so efficiency of the engine is 0.4167