Answer:
1.176
Explanation:
When the bullets impact the mass they become embedded on it, it is a plastic collision, therefore momentum is conserved.
v2 * (M + mb) = v1 * mb
Where
v1: muzzle velocity of the bullet
M: mass of the bob
mb: mass of the bullet
v2: mass of the bob with the bullet after being hit
v2 = v1 * mb / (M + mb)
Upon being impacted the bob will acquire speed v2, this implies a kinetic energy. The bob will then move and raise a height h. Upon acheiving the maximum height it will have a speed of zero. At that point all kinetic energy will be converted into potential energy.
Ek = 1/2 (M + mb) * v2^2
Ep = (M + mb) * g * h
Ek = Ep
1/2 (M + mb) * v2^2 = (M + mb) * g * h
1/2 * (v1 * mb / (M + mb))^2 = g * h
1/2 * v1^2 * mb^2 / (M + mb)^2 = g * h
v1^2 = g *h * (M+ mb)^2 / (1/2 * mb^2)

The height h that it reaches is related to the length L of the pendulum arm and the angle it forms with the vertical.
h = L * (1 - cos(a))

For the 9 mm:

For the 0.44 caliber:

The ratio is 460 / 391 = 1.176
When a force is applied to a member and it is pointed at a joint, the member is in compression. When a force is directed away from a joint that the member is attached to, it is said to be in tension.
<h3>What is
tension?</h3>
The pulling force transmitted axially by a string, rope, chain, or other similar object, or by each end of a rod, truss member, or other similar three-dimensional object, is referred to as tension in physics. Tension can also be described as the action-reaction pair of forces acting at each end of the aforementioned elements. Tension, the opposite of compression, is conceivable.
To measure tension as a transmitted force, an action-reaction pair of forces, or a restoring force, the International System of Units uses newtons (or pounds-force in Imperial units). At the point of attachment to the objects to which the string or rod is connected, the ends of a string or other object that transmits tension will exert forces in the direction of the string.
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The net resultant direct force and angle on the vane is created when the water jet exits the vane at position 2 with 92% of its initial velocity.
<h3>What is mean by velocity?</h3>
- The speed at which a body or object is moving determines its direction of motion. A scalar quantity, speed is primarily. As a matter of fact, velocity is a vector quantity.
- The rate at which distance changes is what it is. It measures the displacement's rate of change. A body's velocity is defined as its speed in a particular direction.
- Velocity is a measure of how quickly a distance changes in relation to time. Having both magnitude and direction, velocity is a vector quantity.
- The rate of change in a body's displacement with respect to time is referred to as velocity. In the SI, m/s is its unit.
Given,
External angle of Curved Vane = 158°
mean velocity at 1 = 12 m/s
Volumetric flow rate = 
mean velocity at 
i) Force exerted in x - friction A C 1 = Volume
![F_{S_x} &=\rho A C_1\left[C_2 \cos \theta-C_1\right] \\](https://tex.z-dn.net/?f=F_%7BS_x%7D%20%26%3D%5Crho%20A%20C_1%5Cleft%5BC_2%20%5Ccos%20%5Ctheta-C_1%5Cright%5D%20%5C%5C)
![&=1000 \times \frac{55}{3600}\left[\left(11.04 \cos 158^{\circ}\right)-12\right]](https://tex.z-dn.net/?f=%26%3D1000%20%5Ctimes%20%5Cfrac%7B55%7D%7B3600%7D%5Cleft%5B%5Cleft%2811.04%20%5Ccos%20158%5E%7B%5Ccirc%7D%5Cright%29-12%5Cright%5D)
i![\rangle F_{\text {sc }}=\supseteq A c_1\left[C_2 \sin \theta\right] \\](https://tex.z-dn.net/?f=%5Crangle%20F_%7B%5Ctext%20%7Bsc%20%7D%7D%3D%5Csupseteq%20A%20c_1%5Cleft%5BC_2%20%5Csin%20%5Ctheta%5Cright%5D%20%5C%5C)






The complete question is:
A horizontal jet of water strikes a curved vane as shown in Figure C.1. The external angle of the curved vane is 158°.The mean velocity and volumetric flow rate of the water jet at position 1 are 12 m/s and 55 m³/h respectively. Due to friction, the water jet leaves the vane at position 2 with 92 % its original velocity.
(i) Direct force exerted by the water jet on the vane in the x - direction.
(ii) Direct force exerted by the water jet on the vane in the y - direction.
(ii) Net resultant direct force and angle on the vane.
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Answer:
It would take approximately 305 s to go to 99% completion
Explanation:
Given that:
y = 50% = 0.5
n = 1.7
t = 100 s
We need to first find the parameter k from the equation below.

taking the natural logarithm of both sides:

Substituting values:

Also
![t^n=-\frac{ln(1-y)}{k}\\t=\sqrt[n]{-\frac{ln(1-y)}{k}}](https://tex.z-dn.net/?f=t%5En%3D-%5Cfrac%7Bln%281-y%29%7D%7Bk%7D%5C%5Ct%3D%5Csqrt%5Bn%5D%7B-%5Cfrac%7Bln%281-y%29%7D%7Bk%7D%7D)
Substituting values and y = 99% = 0.99
![t=\sqrt[n]{-\frac{ln(1-y)}{k}}=\sqrt[1.7]{-\frac{ln(1-0.99)}{2.76*10^{-4}}}=304.6s](https://tex.z-dn.net/?f=t%3D%5Csqrt%5Bn%5D%7B-%5Cfrac%7Bln%281-y%29%7D%7Bk%7D%7D%3D%5Csqrt%5B1.7%5D%7B-%5Cfrac%7Bln%281-0.99%29%7D%7B2.76%2A10%5E%7B-4%7D%7D%7D%3D304.6s)
∴ t ≅ 305 s
It would take approximately 305 s to go to 99% completion
Answer:
Yes
Explanation:
If the Ajax representative fails to correct the previous statement this can cause misrepresentation.