3 years ago

Bridge Reflection:

Engineering

1 answer:

Nataliya [291]3 years ago

4 0

Answer:

IT feels proud to be done making a bridge

Explanation:

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The yield of a chemical process is being studied.The two most important variables are thought to be the pressure and the tempera

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Answer:

<u>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</u>

Download docx

7 0

3 years ago

Two gases—neon and air—are expanded from P1 to P2 in a closed-system polytropic process with n = 1.2. _____ produces more work w

Makovka662 [10]

Answer:

Note that Air requires lesser work

Explanation:

Calculate for general work done

SInce Gas constant 'R' for: Neon = 0.4119KJ/kg.k , and Air = 0.287 kJ/kg·K

Calculate for work done of NEON

Calculate for work done of Air

See solution attached.

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3 years ago

A manufacturer makes two types of drinking straws: one with a square cross-sectional shape, and the other type the typical round

Harlamova29_29 [7]

Answer:

$\frac{Q_{square}}{Q_{circle}} = 0.785$

Explanation:

given data

types of drinking straws

square cross-sectional shape
round shape

solution

we know that both perimeter of the cross section are equal

so we can say that

perimeter of square = perimeter of circle

4 × S = π × D

here S is length and D is diameter

S = $\frac{\pi D}{4}$ ....................1

and

ratio of flow rate through the square and circle is here

$\frac{Q_{square}}{Q_{circle}} = \frac{AV^2}{AV^2}$

$\frac{Q_{square}}{Q_{circle}} = \frac{S^2}{\frac{\pi D^2}{4}}$

$\frac{Q_{square}}{Q_{circle}} = \frac{(\frac{\pi D}{4})^2}{\frac{\pi D^2}{4}}$

$\frac{Q_{square}}{Q_{circle}} = \frac{\pi }{4}$

$\frac{Q_{square}}{Q_{circle}} = 0.785$

4 0

4 years ago

A heat pump designer claims to have an air-source heat pump whose coefficient of performance is 1.8 when heating a building whos

Anit [1.1K]

Answer:

The claim is valid.

Explanation:

Let assume that heat pump is reversible. The coefficient of performance for the heat pump is:

$COP_{HP} = \frac{T_{H}}{T_{H}-T_{L}}$

$COP_{HP} = \frac{300\,K}{300\,K-260\,K}$

$COP_{HP} = 7.5$

The claim is valid as real heat pumps have lower coefficients of performance.

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3 years ago

Which option identifies the concept represented in the following scenario?

dlinn [17]

Answer:

project object

Explanation:

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3 years ago