Answer:
80.16 m/s^2
at t=2 s
x=42.3 m
y=16 m
z=14 m
Explanation:
solution
The x,y,z components of the velocity are donated by the i,j,k vectors.
acceleration is a derivative of velocity with respect to time.
![a_{x}=\frac{d}{dt} v_{x}=\frac{d}{dt}[16t^{2}]=32t\\a_{y}=\frac{d}{dt} v_{y}=\frac{d}{dt}[4t^{3}]=12t^{2} \\a_{z}=\frac{d}{dt} v_{z}=\frac{d}{dt}[5t+2]=5](https://tex.z-dn.net/?f=a_%7Bx%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%20v_%7Bx%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B16t%5E%7B2%7D%5D%3D32t%5C%5Ca_%7By%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%20v_%7By%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B4t%5E%7B3%7D%5D%3D12t%5E%7B2%7D%20%5C%5Ca_%7Bz%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%20v_%7Bz%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B5t%2B2%5D%3D5)
evaluate acceleration at 2 seconds
the magnitude of the acceleration is the square root of the sum of the square of each component of the acceleration.
position is the integral of velocity with respect to time position at a time can be found by taking by taking the definite intergral of each component.
Answer:
Explanation:
A smaller clearance volume means a higher compression. A higher compression means better thermal efficiency. However a compression ratio too high might be troublesome, as it can cause accidental ignition of the fuel-air mix. This is the reason why Otto cycle engines have lower compressions that Diesel engines. In a Diesel engine the mix ignites by compression instead of a spark.
Answer:
I know ship has stream line body
Answer:
14.36((14MPa) approximately
Explanation:
In this question, we are asked to calculate the stress tightened in a bolt to a stress of 69MPa.
Please check attachment for complete solution and step by step explanation
Answer:
hello your question is incomplete attached below is the complete question
answer: There is a hydraulic jump
Explanation:
First we have to calculate the depth of flow downstream of the gate
y1 = 
----------- ( 1 )
Cc ( concentration coefficient ) = 0.61 ( assumed )
Yg ( depth of gate opening ) = 0.5
hence equation 1 becomes
y1 = 0.61 * 0.5 = 0.305 m
calculate the flow per unit width q
q = Q / b ----------- ( 2 )
Q = 10 m^3 /s
b = 2 m
hence equation 2 becomes
q = 10 / 2 = 5 m^2/s
next calculate the depth before hydraulic jump y2 by using the hydraulic equation
answer : where y1 < y2 hence a hydraulic jump occurs in the lined channel
attached below is the remaining part of the solution
