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Anestetic [448]
3 years ago
11

Solve. 5=1/5x−3 Enter your answer in the box. x =

Mathematics
2 answers:
Bad White [126]3 years ago
5 0
X = 40 Im 99.9% sure it in 40 hope it helps!
FrozenT [24]3 years ago
3 0
You must multiply 5x-3 with 5, then you will get

25x-15 = 1
25x = 1+15
25x = 16
x = \frac{16}{25}
x = 0.64
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If f(x)=-9x-3, find f(-5)
Andrews [41]

Answer:

42

Step-by-step explanation:

f(-5) = -9 × (-5) - 3 = 45 - 3 = 42

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below =)

5 0
3 years ago
Please help ASAP !! :)
Mila [183]

Answer:

  1. temperature is decreasing as time passes
  2. x-axis
  3. hot drink temperature (°C)

Step-by-step explanation:

1. Each value of temperature is lower than the one previous, so we can say the temperature is decreasing. We also notice that the rate of decrease is getting smaller, possibly because the temperature is approaching a horizontal asymptote.

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2. The horizontal axis, where temperature is plotted, is conventionally called the x-axis.

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3. The label on the vertical axis is "temperature" and the graph title is "cooling a hot drink ...", so we presume the dependent variable is the temperature of a hot drink.

7 0
3 years ago
Select the correct comparison
seropon [69]

Answer:

pretty sure its d

Step-by-step explanation:

Because a has spread out dots and b has them all towered and neat so d

5 0
3 years ago
To make the chocolate shake, Dona added 40 mL of chocolate syrup,
Vsevolod [243]

Answer:

0.225 L of milk, would be required if she uses 450 m L of water.

Step-by-step explanation:

Here, to make the shake, ingredients used by Dina are:

40 m L of chocolate syrup,

200 m L of milk, and 400 m L of water.

So, here Amount of water used = 2 x ( Amount of Milk used)  .......  (1)

Now,again the amount of water used by Dona = 450 m L

Let us assume the milk used by her  = k m L

⇒ 450 m L = 2 x ( k m L)     ( from (1))

or, 450 = 2  k

⇒  k    = 450/2  = 225

⇒   k   = 225 m L

Also, 1 m L = 0.001 L

So, 225 m L = 225 x  0.001  = 0.225 L

⇒   k   = 0.225  L

Hence, 0.225 L of milk, would be required if she uses 450 m L of water.

5 0
3 years ago
Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
Leya [2.2K]

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6

6 0
3 years ago
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