3 years ago

12x+7<−11 AND5x−8≥4012

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

8 0

Answer:

No solution

Step-by-step explanation:

Given: $12x+7$ and $5x-8\geq 40$

Solve both inequality separately.

$12x+7$ Subtraction property of inequality

$12x$

$x$

and

$5x-8\geq 40$ Addition property of inequality

$5x\geq 40+8$

$5x\geq 48$

$x\geq \dfrac{48}{5}$

Hence, the solution of the compound inequality intersection of both solutions.

Please find attachment for number line solution.

No solution

Law Incorporation [45]3 years ago

6 0

Answer:

No Solution

Step-by-step explanation:

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