Answer:
1. high frequency and high energy.
2. short wavelengths and high frequencies.
3. less energy and long wavelengths.
4. high frequencies and high energy
5. X-rays
6. infrared waves
7. radio waves.
8. Gamma Rays
9. Microwaves
10. infrared waves
Answer:
The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp
Explanation:
<u>Polar moment of Inertia</u>

= 0.14374 in 4
<u>Maximum sustainable torque on the solid circular shaft</u>

=
= 3658.836 lb.in
=
lb.ft
= 304.9 lb.ft
<u>Maximum sustainable torque on the tubular shaft</u>

= 
= 3334.8 lb.in
=
lb.ft
= 277.9 lb.ft
<u>Maximum sustainable power in the solid circular shaft</u>

= 
= 4023.061 lb. ft/s
=
hp
= 7.315 hp
<u>Maximum sustainable power in the tubular shaft</u>

= 
= 3666.804 lb.ft /s
=
hp
= 6.667 hp
Answer:
Light consists of photons, which are produced when an object's atoms heat up. Light travels in waves and is the only form of energy visible to the human eye.
Explanation:
Answer:
Object C has the most potential energy.
Between A and B, we do not know which has more potential energy.
Explanation:
We know the object with the most potential energy and this is the object at C.
Potential energy is the energy due to the position of a body above the ground surface.
The higher a body is above ground, the more its potential energy.
Potential energy = mass x acceleration due to gravity x height
So;
Object C has the most potential energy.
Between A and B, we do not know which has more potential energy.
This is because, the height and mass of the objects are not quantified using numbers.
Potential energy is a function of mass and height and acceleration due to gravity but acceleration due gravity is a constant.
Answer:
T_ac = 6.586 KN
R = 10.51 KN
Explanation:
Given:
- Tension in cable T_ab = 9.1 KN
Find:
- Determine the required tension T in cable AC such that the net effect of the two cables is a downward force at point A
- Determine the magnitude R of this downward force.
Solution:
- Compute the three angles as shown in figure attached, a, B , y:
a = arctan (40/50) = 38.36 degrees
B = arctan (50/30) = 59.04 degrees
y = 180 - 38.36 = 82.6 degrees
- Use cosine rule to calculate R and F_ac as follows:
sin(a) / T_ac = sin(B) / T_ab = sin(y) / R
sin(38.36) / T_ac = sin(59.04) / 9.1 = sin(82.06) / R
T_ac = 9.1 * ( sin(38.36) / sin(59.04) )
T_ac = 6.586 KN
R = 9.1 * ( sin(82.06) / sin(59.04) )
R = 10.51 KN