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Wittaler [7]
3 years ago
5

An object is 9.00 cm tall. The image is 5.76 cm tall, and 14 cm

Physics
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

i would say 9.00 or 5.76

Explanation:

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A neon sign that requires a voltage of 11,000 v is plugged into a 120-v wall outlet. what turns ratio (secondary/primary) must a
Arisa [49]
The equation that relates the voltages and the number of turns in a transformer is
\frac{V_s}{V_p}= \frac{N_s}{N_p}
where V_s = 120 V is the voltage in the secondary coil, V_p=11000 V is the voltage in the primary coil, and N_s and N_p are the number of turns on the secondary and primary coils.

Using the numbers, we find the ratio between the number of turns:
\frac{N_s}{N_p}= \frac{V_s}{V_p}= \frac{120 V}{11000 V}=0.0109
8 0
3 years ago
A rectangular coil with 50 turns of conducting wire and a total resistance of 10.0 Ω initially lies in the yz-plane at time t =
castortr0y [4]

Answer:

a) 43.20V

b) 2.71W/s

c) 40.25s

d) 7.77Nm

Explanation:

(a) The emf of a rotating coil with N turns is given by:

emf=NBA\omega sin(\omega t)

N: turns

B: magnitude of the magnetic field

A: area

w: angular velocity

the emf max is given by:

emf_{max}=NBA\omega=(50)(1.80T)(0.200m*0.100m)(24.0rad/s)\\\\emf_{max}=43.20V

(b) the maximum rate of change of the magnetic flux is given by:

\frac{d\Phi_B}{dt}=\frac{d(A\cdot B)}{dt}=\frac{d}{dt}(ABcos\omega t)=AB\omega sin(\omega t)\\\\\frac{d\Phi_B}{dt}_{max}=(\pi(0.200*0.100))(1.80T)(24.0rad/s)=2.71\frac{W}{s}

(c) emf(t=0.050s)=(50)(1.80T)(0.200m*0.100m)(24rad/s)sin(24.0rad/s(0.050s))\\\\emf(t=0.050s)=40.26V

(d) The torque is given by:

\tau=NABIsin\theta\\\\NAB\omega=emf_{max}\\\\\tau=\frac{emf_{max}}{\omega}\frac{emf_{max}}{R}\\\\\tau=\frac{(43.20V)^2}{(24.0rad/s)(10.0\Omega)}=7.77Nm

3 0
3 years ago
The type of error which is corrective
vodka [1.7K]

Answer:

ummm i dont know what...

4 0
3 years ago
Can someone help answers these questions? <br> (I attached the pictures)
RoseWind [281]

Nothing works if Switch-3 is open.

-- None

-- A, E, F, G

-- None

-- A, B, E, F, G

-- A, C, D, E, F, G (everything except B)

3 0
3 years ago
Recall that weight is a force and is equal to m*g, where g is the acceleration due to gravity exerted by the Earth near the Eart
Marysya12 [62]

Answer:

145.43 N

Explanation:

Weight is given by (mg)

where m = mass of the body

g = acceleration due to gravity

mass is constant everywhere and is equal to 77.1 kg, both on the earth and on the moon.

But the acceleration due to gravity exerted by the moon near the moon's surface is 16.6% that of Earth,

g(moon) = 0.166 g(earth) = 0.166 × 9.8 = 1.6268 m/s²

Weight on the moon = mg(moon) = (77.1×1.6268) = 125.43 N

3 0
3 years ago
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