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2 years ago

How much force must you apply to give the go cart an acceleration of 0.9m/s^2

1 answer:

5 0

It's dependent on the mass. You can fimd the force needed using the formula F = ma. Where F is force, m is mass of the cart and a is the acceleration (0.9m/s^2). The heavier it is the more force you are going to need. Remember unit of force is N

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mario62 [17]

C liquid at room temperature

4 0

3 years ago

A boy weighs 40 kilograms. He runs at a velocity of 4 meters per second north. Which is his momentum?

Artist 52 [7]

The formula for momentum is mass times velocity. Simply, we just multiply the given values:
p = mv
p = 40 kg x 4 m/s
p = 160 kg m/s

Other units for momentum is N s.
p = 160 N s

4 0

2 years ago

A disk shaped grindstone of mass 3.0 kg and radius 8 cm is spinning at 600 rpm. After the power is shut off the frictional torqu

seropon [69]

Answer:

$\theta=50\ revolution$

Explanation:

It is given that,

Mass of the grindstone, m = 3 kg

Radius of the grindstone, r = 8 cm = 0.08 m

Initial speed of the grindstone, $\omega_i=600\ rpm=62.83\ rad/s$

Finally it shuts off, $\omega_f=0$

Time taken, t = 10 s

Let $\alpha$ is the angular acceleration of the grindstone. Using the formula of rotational kinematics as :

$\alpha =\dfrac{\omega_f-\omega_i}{t}$

$\alpha =\dfrac{0-62.83}{10}$

$\alpha =-6.283\ rad/s^2$

Let $\theta$ is the number of revolutions of the grindstone after the power is shut off. Now using the third equation of rotational kinematics as :

$\omega_f^2-\omega_i^2=2\alpha \theta$

$\theta=\dfrac{\omega_f^2-\omega_i^2}{2\alpha }$

$\theta=\dfrac{-62.83^2}{2\times -6.283}$

$\theta=314.15\ radian$

$\theta=49.99\ revolution$

$\theta=50\ revolution$

So, the number of revolutions of the grindstone after the power is shut off is 50.

7 0

3 years ago

Some one help my science homework is due tomorrow and I'm so stuck with question 8-9, and 11-12

yuradex [85]

Off the top of my head, I only know 9 and 11, so I'll answer those two.

9) A heterotroph is an organism that relies on other organisms for food/energy
An autotroph can produce its own food from inorganic compounds (light)

11) Vascular plants have specialized tubes for transporting nutrients
Nonvascular plants do not have such tubes and are simpler

5 0

3 years ago

Space Station Suppose a space-station is designed in s shape of a torus such as the one depicted in Stanley Kubrick's "2001: A s

yaroslaw [1]

Answer:

w = 3.2 rev / min

Explanation:

For this exercise we will use the centrine acceleration equal to the acceleration of gravity

a = v² / r

Angular and linear variables are related.

v = w r

Let's replace

a = w² r = g

w = √ g / r

r = d / 2

r = 175/2 = 87.5 m

w = √( 9.8 / 87.5)

w = 0.3347 rad / s

Let's reduce to rotations per min

w = 0.3347 rad / s (1 rov / 2pi rad) (60 s / 1 min)

w = 3.2 rev / min

Suppose the space station rotates counterclockwise, we have two possibilities for the car

The first car turns counterclockwise (same direction of the station

$v_{c}$ = $w_{c}$ r

[texwv_{c}[/tex] = $v_{c}$ / r

[texwv_{c}[/tex] = 25.0 / 87.5

[texwv_{c}[/tex] = 0.286 rad / s

When the two rotate in the same direction their angular speeds are subtracted

w total = w -[texwv_{c}[/tex]

w total = 0.3347 - 0.286

w total= 0.487 rad / s

The car goes in the opposite direction of the station the speeds add up

w = 0.3347 + 0.286

w = 0.62 rad / s

From this values we can see that the person feels a variation of the acceleration of gravity, feels that he has less weight when he goes in the same direction of the season and that his weight increases when he goes in the opposite direction to the season.

3 0

3 years ago