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devlian [24]
2 years ago
15

Which of the following expressions has a value between 5 and 6.

Mathematics
2 answers:
Airida [17]2 years ago
8 0
So listen to this logic
lets say you have 3 numbers, m,a,x where they are all positivie
m>a>x
therefor
m^2>a>2>x^2
if m and a and x are square roots, therefor we can reverse the square root
confusing sorry

square 5 and 6
5^2=25
6^2=36

the number betwe 25 and 36

that would be 32

answer is √32

goes like this
5^2<32<6^2
sqrt both sides
5<√32<6

answer is √32
Sladkaya [172]2 years ago
3 0

Answer:

\sqrt{32}

Step-by-step explanation:

expressions has a value between 5 and 6.

First we take perfect square numbers

WE know \sqrt{25} = 5

\sqrt{36} = 6

We need to find a value between 5  and 6

That means we need to find a value between \sqrt{25} \  and \ \sqrt{36}

\sqrt{17} does not lie between \sqrt{25} \ and \ \sqrt{36}

\sqrt{32}  lie between \sqrt{25} \ and \ \sqrt{36}

\sqrt{60} does not lie between \sqrt{25} \ and \ \sqrt{36}

\sqrt{1125} does not lie between \sqrt{25} \ and \ \sqrt{36}

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<img src="https://tex.z-dn.net/?f=6%20-%205x%20%2B%206%20%3D%204" id="TexFormula1" title="6 - 5x + 6 = 4" alt="6 - 5x + 6 = 4" a
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\bf 6-5x+6=4\implies -5x+12=4\implies \stackrel{\textit{adding 5x to both sides}}{12=4+5x}\\\\\\\stackrel{\textit{subtracting 4 to both}}{8=5x}\implies \cfrac{8}{5}=x\implies 1\frac{3}{5}=x

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