(4x^3-4+7x)-(2x^3-x-8) is equivalent to expression ?

If x/y = -3, then find x²/y² + y²/x².

sladkih [1.3K]

Answer:

9.11

Step-by-step explanation:

Given that,

$\dfrac{x}{y}=-3$

We need to find the value of $\dfrac{x^2}{y^2}+\dfrac{y^2}{x^2}$

The value of $\dfrac{y}{x}=\dfrac{-1}{3}$

So,

$\dfrac{x^2}{y^2}+\dfrac{y^2}{x^2}=(\dfrac{x}{y})^2+(\dfrac{y}{x})^2\\\\=(-3)^2+(\dfrac{-1}{3})^2\\\\=9+\dfrac{1}{9}\\\\=9.11$

So, the required answer is equal to 9.11.

6 0

3 years ago

A given line has the equation 10x + 2y = −2.

julia-pushkina [17]

Y = -5x + 12 ...............

7 0

3 years ago

Read 2 more answers

The price of a stock decreased by $20\%$ in 2001, and then decreased by $20\%$ in 2002. What percent increase in 2003 will resto

Marysya12 [62]

oh come on

(read the comments(all of them))

7 0

3 years ago

Given: <br><br>OA⊥OB, DE tangent at D<br><br>Prove: ∠ECD≅∠EDC

Harlamova29_29 [7]

Answer:

x

Step-by-step explanation:

5 0

3 years ago

Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5

Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

$\boxed{ \mathsf{ \red{y - y_{1} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1}) }}}$

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

$\mathsf{\implies y - ( - 1.5) = \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}$

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

$\mathsf{\implies (y + 1.5) = \frac{0 + 1.5}{2.5 } (x )}$

$\mathsf{\implies y + 1.5 = \frac{ 1.5}{2.5 } x }$

$\mathsf{\implies y + 1.5 = \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x }$

$\mathsf{\implies y + 1.5 = \frac{ 3}{5 } x }$

multiplying both sides by 5

$\mathsf{5y + 7.5 = 3x}$

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

$\mathsf{\implies5(0) + 7.5 = 3(0)}$

$\mathsf{\implies0 + 7.5 = 0}$

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

$\mathsf{\implies7.5 > 0}$

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

$\mathsf{5y + 7.5 > 3x}$

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

that is the last option

5 0

3 years ago