The length of line segment l n on which point m lines in between is 64 units. Option 4 is the correct option.
<h3>What is the length of line segment?</h3>
Length of a line segment is the distance of both the ends of it.
Point m lies between points l and n on line segment l n .
- The space between l and m is 10x 8.
- The space between m and n is 5x -4.
The value of line segment LN is,
The sum of LM and LN is equal to the line segment LN. Thus,
Put this value of x in the equation of line segment LN,
Thus, the length of line segment l n on which point m lines in between is 64 units. Option 4 is the correct option.
Learn more about the line segment here;
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The answer for that is
x= 3,2
Put simply, you have to work backwards in making the equations. Start with the product of 8/3 and 9.
*9 Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
(*9)*
, or dividing everything by 4.
(*9)/4
Finally, subtract three.
The final equation would read:
((*9)*)-3Using PE(M/D)(A/S), we'd start with
*9
3 and 9 cancel out to be 1 and 3, leaving us with
, or 8, and 3 and this part of the equation reading 8*3, which is 24.
The next step is
, which is 6.
Lastly we subtract 3 from six, leaving us 3.
Answer:
So we can find this probability:
And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:
Step-by-step explanation:
Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info
Where 
and 
We can begin finding this probability this probability
For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:
And the best way to solve this problem is using the normal standard distribution and the z score given by:
And we can find the z scores for each limit and we got:
So we can find this probability:
And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:
