Use the x-intercept method to find all real solutions of the equation.
1 answer:
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<span><u><em>Answer:</em></u>
The first group would have <u>12 cans</u>
The second group would have <u>16 cans</u>
<u><em>Explanation:</em></u>
We know that the total number of cans in 28 and that the ratio between the two groups is 3:4
<u>This means that:</u>
If the first group has 3x cans, then the second group would have 4x cans.
<u>Now, we would solve for x:</u>
3x + 4x = 28
7x = 28
x = </span>
<span>
x = 4 cans
<u><em>Therefore:</em></u>
The first group would have 3x = 3(4) = 12 cans
The second group would have 4x = 4(4) = 16 cans
Hope this helps :)</span>
The first group would have <u>12 cans</u>
The second group would have <u>16 cans</u>
<u><em>Explanation:</em></u>
We know that the total number of cans in 28 and that the ratio between the two groups is 3:4
<u>This means that:</u>
If the first group has 3x cans, then the second group would have 4x cans.
<u>Now, we would solve for x:</u>
3x + 4x = 28
7x = 28
x = </span>
x = 4 cans
<u><em>Therefore:</em></u>
The first group would have 3x = 3(4) = 12 cans
The second group would have 4x = 4(4) = 16 cans
Hope this helps :)</span>