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natulia [17]
3 years ago
7

Choose the correct expressions using the fewest number of bases possible that are equivalent to the current expression. (Select

all that apply); (Hint: There are 2 correct choices) Question 2 options: 53+2 53×52 53×2 55

Mathematics
2 answers:
kykrilka [37]3 years ago
5 0

Answer:

\huge \boxed{\mathrm{5^{3+2} \ \ \ \ 5^5 }}

Step-by-step explanation:

5³ × 25

25 can be written as a base of 5.

5³ × 5²

We need expressions with fewest number of bases possible.

Apply exponent rule : a^b \times a^c = a^{b+c}

5^{3+2}

Add exponents.

5^5

yKpoI14uk [10]3 years ago
4 0

Answer:

The answer is easy its 53 times 2 and 52 times 2

Step-by-step explanation:

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Deffense [45]
Start by laying out the 12.
The neighbors of 12 must be 11 and 10.
The neighbor of 11 must be 9, and the neighbor of 10 must be 8, and so on and so forth, until you get a unique arrangement.

3 0
3 years ago
13 candy bars weigh 26 ounces. what is the weight of 35 candy bars?
anygoal [31]
26 oz/13 bars = 2 oz/1 bar

Each bar weighs 2 oz

multiply the amount of bars to the amount they weigh:

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hope this helps
6 0
3 years ago
There are 32 red or blue marbles in a bag. The number of red marbles is 4 more than 3 times the number of blue marbles. Write an
eimsori [14]

Answer:

# red marbles = 25

# blue marbles = 7

Step-by-step explanation:

r + b = 32

r = 4 + 3b

substitute '4 + 3b' for 'r' in the 1st equation

4 + 3b + b = 32

4 + 4b = 32

4b = 28

b = 7

red = 32 - 7

r = 25

5 0
3 years ago
Two integers, a and b have a product of 15. what is the least possible sum of a and b?
Neporo4naja [7]
If they're integers, that means they can't be fractions (such as 15/2 and 2).

So the only couples of integers that, when multiplied, result in 15 are:

1 and 15
5 and 3.

(there are no other possibilities as both 5 and 3 are not divisible further).
The smaller of the two sums (15+1; 5+3) is 5+3=8.

The least possible sum of a and b is 8.
7 0
3 years ago
Determine the zeros of the following function.
dezoksy [38]
This is a Function cause x doesn't repeat
4 0
3 years ago
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