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suter [353]
3 years ago
10

If a piece of wood with a length of five feet is cut into six equal pieces, what is the length of each piece?

Mathematics
1 answer:
lina2011 [118]3 years ago
6 0

5 feet = 60 in

60 in ÷6 = 10 in per piece

10 inches is 5/6 of a foot, so the answer is B.

Hope this helps!

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10.) Your dad is planning to increase the area of your rectangular patio. Your current patio is 8
belka [17]

Answer:

x = 3.69 feet

11.69 x 13.69 feet

Step-by-step explanation:

new area = (8 x 10) x 2 = 160

(8 + x)(10 + x) = 160

80 + 8x + 10x + x² = 160

combine like terms:

x² + 18x - 80 = 0

factor:

(x - 3.69)(x + 21.69) = 0

x = 3.69

6 0
3 years ago
(b) Ali uses 11% of his $2345 to buy a television.
Fiesta28 [93]

Answer:

$257.95

Step-by-step explanation:

8 0
3 years ago
Mr. JB has a rectangular lot that measures 550 meters by 550 km. What is the area of the land in square meter. He i selling the
Bingel [31]

9514 1404 393

Answer:

  15/22 peso/m^2 ≈ 0.68182 peso/m^2

Step-by-step explanation:

The area is the product of the dimensions. 1 km = 1000 m.

  A = (550 m)(550·1000 m) = 302,500,000 m^2

The price per square meter is ...

  206,250,000/302,500,000 peso/m^2

  = 15/22 peso/m^2 ≈ 0.68182 peso/m^2

7 0
3 years ago
HELP!!WILL GIVE BRAINLIEST
vazorg [7]

Answer:

m∠A = 100

m∠C = 50

Step-by-step explanation:

let 'x' = m∠A

let 'x/2' = m∠C

x + x/2 + 30 = 180

3/2x = 150

x = 150(2) / 3

x = 300/3

x = 100

m∠A = 100°

m∠C = 100/2 or 50°

5 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
Read 2 more answers
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