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nalin [4]
4 years ago
11

Evaluate 2b^2-4a+4a^2 for a= 3 and b= -8

Mathematics
2 answers:
JulijaS [17]4 years ago
8 0

Hey there!!

The given equation : 2b² - 4a + 4a²

Where, a = 3 and b = -8

Now, we will have to substitute these values in the equation given above

2 ( - 8 )² - 4 ( 3 ) + 4 ( 3 ) ²

( -8 )² = 64

Because -8 × -8 = 64 . As ( - ) × ( - ) = ( + )

negative × negative = positive

Now, moving on

2 ( 64 ) - 4 ( 3 ) + 4 ( 9 )

128 - 12 + 36

116 + 36

<h2>The required answer is 152. </h2><h3>Hope my answer helps!!</h3>
masha68 [24]4 years ago
5 0
Given a = 3 and b = - 8 ,


= > 2b² - 4a + 4a²

= > 2( - 8 )² - 4( 3 ) + 4( 3 )²

= > 2( 64 ) - 4( 3 ) + 4( 9 )

= > 128 - 12 + 36

= > 116 + 36

= > 152



\:


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Answer:

The bearing is N 55.62° W

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