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3 years ago

why would a soft container protect an egg from a drop better than a hard container? (use physics terms!)

Physics

1 answer:

jeyben [28]3 years ago

6 0

The average force exerted on the egg is smaller for a soft container

Explanation:

When the egg falls down and reaches the ground, its change in momentum is given by

$\Delta p = m\Delta v$

where

m is the mass of the egg

$\Delta v$ is the change in velocity

According to the impulse theorem, the change in momentum is equal to the impulse exerted by the floor on the egg:

$\Delta p = I = F \Delta t$

where

F is the average force exerted on the egg

$\Delta t$ is the duration of the collision

The equation can be rewritten as

$F=\frac{\Delta p}{\Delta t}$

A soft container is able to increase the duration of the collision, $\Delta t$ , compared to a hard container. Since the change in momentum of the egg, $\Delta p$ , is the same (we assume the same initial conditions), this means that the ratio $\frac{\Delta p}{\Delta t}$ is smaller for a soft container, and therefore the average force exerted on the egg is also smaller.

Learn more about impulse:

brainly.com/question/9484203

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AleksandrR [38]

Answer: The penetrating power of alpha rays, beta rays, and gamma rays varies greatly. Alpha particles can be blocked by a few pieces of paper. Beta particles pass through paper and Gamma rays are the most difficult to stop and require concrete, lead, or other heavy shielding to block them.

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3 years ago

. The free throw line in basketball is 4.57 m (15 ft) from the basket, which is 3.05 m (10 ft) above the floor. A player standin

pentagon [3]

Answer:

$\theta = 67.22 degree$

Explanation:

Let say the ball is projected at an angle with horizontal

So here two components of the velocity of the ball is given as

$v_x = 8.15 cos\theta$

$v_y = 8.15 sin\theta$

now the displacement in x direction is given as

$x = v_x t$

$4.57 = (8.15 cos\theta)t$

in y direction it is given as

$y = y_o + v_y t - \frac{1}{2}gt^2$

$3.05 = 2.44 + (8.15 sin\theta) t - 4.9 t^2$

now from above two equations

$0.61 = 4.57 tan\theta - 4.9(\frac{4.57}{8.15 cos\theta})^2$

$0.61 = 4.57 tan\theta - 1.54(1 + tan^2\theta)$

$1.54 tan^2\theta - 4.57 tan\theta + 2.15 = 0$

$\theta = 67.22 degree$

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3 years ago

Two cars, with the same mass and traveling at the same speed, hit large trees head-on. One car has a rigid body that undergoes l

nordsb [41]

The crumple zones in the second car will improve the chance of survival of the driver because it will act as shock absorber, reducing the impact of the force on the driver.

<h3>Newton's third law of motion</h3>

According to Newton's third law of motion, action and reaction are equal and opposite.

The car with rigid body will exert maximum force to the driver while the car with crumple zone will exert lesser force to the driver since the crumple zone will act as shock absorber, reducing the impact of the force on the driver.

Thus, the crumple zones in the second car will improve the chance of survival of the driver because it will act as shock absorber, reducing the impact of the force on the driver.

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2 years ago

A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75

8_murik_8 [283]

Complete Question

A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutions. At what rate is the flywheel spinning when the power comes back on(in rpm)? How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on, and how many revolutions would the wheel have made during this time?

Answer:

$\theta=274rev$

Explanation:

From the question we are told that:

Angular velocity $\omega=510rpm$

Mass $m=40.kg$

Diameter d $75=>0.75m$

Off Time $t=40.0s$

Oscillation at Power off $N=210$

Generally the equation for Angular displacement is mathematically given by

$\theta_{\infty}=\frac{w+w_0}{t}t$

$w=\frac{2*\theta_{\infty}}{t}-w_0$

$w=\frac{28210}{40*(\frac{1}{60})}-510$

$w=120rpm$

Generally the equation for Time to come to rest is mathematically given by

$t=(\frac{\omega_0}{\omega_0-\omega})t$

$t=(\frac{510}{510-120rpm})(40.0)(\frac{1}{60})$

$t=0.87min$

Therefore Angular displacement is

$\theta =(\frac{120+510}{2})0.87$

$\theta=274rev$

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3 years ago

In the bohr model, what is the ratio of its kinetic energy to its potential energy?

stich3 [128]

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Therefore KE/PE = 1/2, no matter what state the electron is in.

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3 years ago

why would a soft container protect an egg from a drop better than a hard container? (use physics terms!)​

why would a soft container protect an egg from a drop better than a hard container? (use physics terms!)