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Genrish500 [490]
3 years ago
5

A 1.6 kg bicycle wheel with a radius of 0.31 m turns at a constant angular speed of 27 rad/s when a(n) 0.33 kg reflector is at a

distance of 0.19 m from the axle. What is the angular speed of the wheel when the reflector slides to a distance of 0.26 m from the axle? Answer in units of rad/s.
Physics
1 answer:
skad [1K]3 years ago
3 0

Answer:

angular speed = 25.393 rad/s

Explanation:

Given Data:

weight of bicycle wheel is 1.6 kg

radius of bicycle wheel is 0.31 m

angular speed is 27 rad/s

weight of reflector uis 0.33 kg

reflector distance from axle is 0.19 m

we know that moment of inertia between two mass is calculated as

Moment of inertiaI1 = \frac{1}{2} { MR^2 +m r^2 }

= \frac{1}{2}[ {1.6*0.31^2 + 0.33* 0.19^2}]

= 0.0828

Moment of inertia I2

= \frac{1}{2}[ {1.6*0.31^2 + 0.33* 0.26^2}]

= 0.088

\frac{I1}{I2} = 0.9405

\omega =  {\frac{I1}{I2} \omega _1

= 0.9405 \times 27

             = 25.393 rad/s

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Explanation:

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mass of Projectile m_2=234 kg

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Launch angle \theta =31.3^{\circ}

As the External Force is zero therefore we can conserve momentum

Initially both Projectile and cannon is at rest

Conserving momentum in horizontal direction

m_1u_1+m_2u_2=m_1v_1+m_2v_2\cos 31.3

0+0=6475.91\times v_1+234\times 170\cdot \cos (31.3)

v_1=-\frac{234\times 170\cdot \cos (31.3)}{6475.91}

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Read 2 more answers
Sally and ner pet puagie go everywnere
FrozenT [24]

a)The total distance she walks will be 1100 m.

b)The magnitude and direction of the budgie's path will be 854.4 m at 69.44°.

c)Sally's average speed for the journey will be 2.82 m/sec

d)The average velocity of Sally's budgie willl be 2.19 m/sec North of East.

<h3>What is displacement?</h3>

Displacement is defined as the shortest distance between the two points.

Distance travelled in north direction,d₁ = 8.0 x 10² m

Time elapsed  travelled in north direction,t₁ = 5.0 minutes

Distance travelled in east direction,d₂ = 0.30 km = 3.0 × 10² m

Time elapsed  travelled in east direction,t₂= 1.5 minutes

The total distance she walks,d =? m

The magnitude and direction of the budgies path will be, D

Sally's average speed for the journey, \rm S_{avg}

The average velocity of Sally's budgie,\rm V_{avg}

a)

The total distance she walks is found as;

d=d₁+d₂

d=800 m +300 m

d = 1100 m

b)

The magnitude and direction of the budgies path will be;

\rm D = \sqrt{d_1 ^2 + d_2^2 } \\\\ D = \sqrt{800^2 +300^2 } \\\\ D = 854.4 \ m

The direction of the displacement is;

\rm   \theta  = tan^{-1} \frac{800}{300} \\\\ \theta = tan^{-1}(2.6) \\\\ \theta = 69.44 ^ 0

c)journey is found as;

Sally's average speed for the

\rm S_{avg}  = \frac{d}{t} \\\\  S_{avg}  =\frac{100}{300+900} \\\\  S_{avg}  =2.82 \ m/sec<em>
</em>

d)

The average velocity of Sally's budgie is found as;

\rm V_{avg}  = \frac{854.4}{300+ 900 } \\\\ V_{avg}  = 2.19 \ m/sec North of east

Hence, the total distance she walks, the magnitude and direction of the budgie's path, Sally's average speed, and the average velocity of Sally's budgie will be 1100 m,854.4 m at 69.44°,2.82 m/sec, and 2.19 m/sec North of East.

To learn more about displacement refer to the link;

brainly.com/question/10919017

#SPJ1

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