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Genrish500 [490]
3 years ago
5

A 1.6 kg bicycle wheel with a radius of 0.31 m turns at a constant angular speed of 27 rad/s when a(n) 0.33 kg reflector is at a

distance of 0.19 m from the axle. What is the angular speed of the wheel when the reflector slides to a distance of 0.26 m from the axle? Answer in units of rad/s.
Physics
1 answer:
skad [1K]3 years ago
3 0

Answer:

angular speed = 25.393 rad/s

Explanation:

Given Data:

weight of bicycle wheel is 1.6 kg

radius of bicycle wheel is 0.31 m

angular speed is 27 rad/s

weight of reflector uis 0.33 kg

reflector distance from axle is 0.19 m

we know that moment of inertia between two mass is calculated as

Moment of inertiaI1 = \frac{1}{2} { MR^2 +m r^2 }

= \frac{1}{2}[ {1.6*0.31^2 + 0.33* 0.19^2}]

= 0.0828

Moment of inertia I2

= \frac{1}{2}[ {1.6*0.31^2 + 0.33* 0.26^2}]

= 0.088

\frac{I1}{I2} = 0.9405

\omega =  {\frac{I1}{I2} \omega _1

= 0.9405 \times 27

             = 25.393 rad/s

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Answer:

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the change at the moment is

          Δp = 45000

because the end the car is stopped

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          P₀ ’= m v

         p₀ '= 60 30

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2) of the momentum change impulse ratio

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              I = -45000 N s

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3) the object that give the momentum to stop the wall motoring

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Answer:

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Explanation:

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RoseWind [281]

Answer:

a) \Delta U_{g} = 12.945\,J, b) \Delta U_{k} = 12.945\,J, c) k = 2930.059\,\frac{N}{m}

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k = \frac{2\cdot (12.945\,J)}{(0.094\,m)^{2}}

k = 2930.059\,\frac{N}{m}

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