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jarptica [38.1K]

3 years ago

5

The famous astronomer, Kepler, determined that the planetary orbits were: 1. ellipses 2. circles 3. epicentric 4. geocentric

1 answer:

Yanka [14]3 years ago

3 0

Answer:

geocentric

i hope this helps!!!!

Explanation:

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kaheart [24]

Answer:

Please selection one of the following

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2 years ago

An apple with a mass of 0.95 kilograms hangs from a tree branch 3.0 meters above the ground.if it falls to the ground, what is t

NeTakaya

KE=1/2mv^2
KE=1/2x0.95x3=1.425

5 0

3 years ago

5. Three children are at work. One is pushing a chair, another is pushing the sofa and the third one is pushing an empty trolley

katen-ka-za [31]

Answer:

sofa

Explanation:

because the sofa is heavy and the amount of friction is high due to the amount of opposite friction is pushing it back

4 0

3 years ago

A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne

kati45 [8]

Answer:

The average emf that will be induced in the wire loop during the extraction process is 37.9 V

Explanation:

The average emf induced can be calculated from the formula

$Emf = -N\frac{\Delta \phi}{\Delta t}$

Where $N$ is the number of turns

$\Delta \phi$ is the change in magnetic flux

$\Delta t$ is the time interval

The change in magnetic flux is given by

$\Delta \phi = \phi _{f} - \phi _{i}$

Where $\phi _{f}$ is the final magnetic flux

and $\phi _{i}$ is the initial magnetic flux

Magnetic flux is given by the formula

$\phi = BAcos(\theta)$

Where $B$ is the magnetic field

$A$ is the area

and $\theta$ is the angle between the magnetic field and the area.

Initially, the magnetic field and the area are pointed in the same direction, that is, $\theta = 0^{o}$

From the question,

B = 1.5 T

and radius = 15.0 cm = 0.15 m

Since it is a circular loop of wire, the area is given by

$A = \pi r^{2}$

∴ $A = \pi (0.15)^{2}$

$A = 0.0225\pi$

∴ $\phi_{i} = (1.5)(0.0225\pi)cos(0^{o} )$

$\phi_{i} = (1.5)(0.0225\pi)$

( NOTE: $cos (0^{o}) = 1$ )

$\phi_{i} = 0.03375\pi$ Wb

For $\phi_{f}$

The field pointed upwards, that is $\theta = 90^{o}$ . Since $cos (90^{o}) = 0$

Then

$\phi_{f} = 0$

Hence,

$\Delta \phi = 0- 0.03375\pi$

$\Delta \phi = - 0.03375\pi$

From the question

$\Delta t = 2.8 ms = 2.8 \times 10^{-3} s$

Here, $N$ = 1

Hence,

$Emf = -N\frac{\Delta \phi}{\Delta t}$ becomes

$Emf = -(1)\frac{-0.03375\pi}{2.8 \times 10^{-3} }$

$Emf = 37.9 V$

Hence, the average emf that will be induced in the wire loop during the extraction process is 37.9 V.

5 0

3 years ago

One of the leading causes of permanent damage leading to hearing impairment is _____.

Maslowich

One of the leading causes of hearing impairment that's due to damage
of the ear machinery is prolonged exposure to loud noise or loud music,
which damage the tiny hair cells that stimulate nerve endings in the inner ear.
Trust me.

6 0

3 years ago

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