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jarptica [38.1K]

3 years ago

5

The famous astronomer, Kepler, determined that the planetary orbits were: 1. ellipses 2. circles 3. epicentric 4. geocentric

1 answer:

Yanka [14]3 years ago

3 0

Answer:

geocentric

i hope this helps!!!!

Explanation:

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A 50 mm diameter steel shaft and a 100 mm long steel cylindrical bushing with an outer diameter of 70 mm have been incorrectly s

BARSIC [14]

Answer:

The axial force is $P = 15.93 k N$

Explanation:

From the question we are told that

The diameter of the shaft steel is $d = 50mm$

The length of the cylindrical bushing $L =100mm$

The outer diameter of the cylindrical bushing is $D = 70 \ mm$

The diametral interference is $\delta _d = 0.005 mm$

The coefficient of friction is $\mu = 0.2$

The Young modulus of steel is $207 *10^{3} MPa (N/mm^2)$

The diametral interference is mathematically represented as

$\delta_d = \frac{2 *d * P_B * D^2}{E (D^2 -d^2)}$

Where $P_B$ is the pressure (stress) on the two object held together

So making $P_B$ the subject

$P_B = \frac{\delta _d E (D^2 - d^2)}{2 * d* D^2}$

Substituting values

$P_B = \frac{(0.005) (207 *10^{3} ) * (70^2 - 50^2))}{2 * (50) (70) ^2 }$

$P_B = 5.069 MPa$

Now he axial force required is

$P = \mu * P_B * A$

Where A is the area which is mathematically evaluated as

$\pi d l$

So $P = \mu P_B \pi d l$

Substituting values

$P = 0.2 * 5.069 * 3.142 * 50 * 100$

$P = 15.93 k N$

8 0

4 years ago

When the compasses are moved close to a wire with a current which will the compasses point

Sindrei [870]

<span>In this demonstration, there is a single compass and a piece of wire that is perpendicular to the plane that the compass sits on. The wire with current flowing through it can alter the direction the compass needle points.</span>

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4 years ago

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Brlan is repairing an old alarm clock. He needs to replace a device that converts the electric energy into sound energy. Which o

Brums [2.3K]

The answer is buzzer

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3 years ago

Solve the inequality. x/3 is greater than or equal to - 6. a. x ≥ –9 b. x ≥ 9 c. x ≥ –18 d. x ≤ –18

NISA [10]

To get x on its own, you times the 3 over to the other side so the 3 cancels out on the LHS.

~ x greater than or equal to -18

(C)

6 0

3 years ago

When NASA was communicating with astronauts on the Moon, the time from sending on the Earth to receiving on the moon was 1.33 s.

frez [133]

To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description, which determine the velocity, such as the displacement of a particle as a function of time, that is to say

$v = \frac{x}{t}\rightarrow x = v*t$

Where,

x = Displacement

v = Velocity

t = Time

Our values are given as,

$v=3*10^8m/s$

$t = 1.33 s$

Replacing we have that,

$x=v*t$

$x=(3*10^8)(1.33)$

$x = 399'000.000m$

Therefore the distance from Earth to the Moon is 399.000 km

5 0

3 years ago