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11111nata11111 [884]
3 years ago
15

How did bosses and political machines control city governments?

Business
1 answer:
inessss [21]3 years ago
8 0

Bosses and political machines controlled the city governments using intimidation. Bribery and corruption were used and Assassinations happened. labor unions formed to control the local governments.

Explanation:

During the late 1800s, city bosses commonly assumed control over city governments. They did not gain power legally, and the bosses were not elected to office. They used blackmail and bribery to convince legal city officials to grant favors to and to follow the wishes of the city bosses.

Political machine, in U.S. politics is a party organization, headed by a single boss or a small autocratic group, that commands enough votes to maintain political and administrative control of a city, county, or state. Examples of such Political machine is Tammy Hall in New York city which provided housing facility to the immigrants and gained their loyal support.

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what are the two fundamental qualitative characteristics that make accounting information useful for decision making?
Charra [1.4K]

Answer:

The answer is relevance and faithful representation.

Explanation:

Accounting information that is not relevant useful.

Relevance is when the accounting information in timely and use for taking major business and economic decisions.

Another one is faithful representation. Accounting information must be faithfully represented. It must be objective and free from bias.

If Accouting information is to be faithfully represented, it must have the following:

1. Completeness. There must be full disclosure of information. No material item or information must be omitted.

2. Error-free It must be 99percent error free.

3. It must be free from bias. Objectivity is the key.

8 0
3 years ago
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Artemon [7]

Answer:

a. True

Explanation:

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly different when it comes to the number of defects present, which is a true statement because as we know process sigma indicates the process variation and is measured in terms of data units, while process sigma count Z, or process sigma level, is a count with no unit of measure and sigma is a statistical term that measures how much a process varies from perfection, based on the number of defects per million units. And also we know that a six sigma process is 1 in which 99.99966 percent of all chances to provide some characteristics of a part are statistically assumed to be free regarding defects.

5 0
3 years ago
Estimate the liquid density (g/cm3) of propane at 298 K and 10 bar. Compare the price per kilogram of propane to the price of re
Deffense [45]

Answer:

Density of propane = 17.8 g/L

Propane is more priced than gasoline

Explanation:

Given:

Temperature, T = 298 K

Pressure, P = 10 bar = 0.987 × 10 = 9.87 atm

now,

Molar mass of propane, M = 44.1 g/mol

From ideal gas law

⇒ PV = nRT

here,

n is the number of moles

R is the ideal gas constant = 0.0821 L.atm/mol.K

also,

Density, D = \frac{\textup{Mass}}{\textup{Volume(V)}}

or

V = \frac{\textup{Mass}}{\textup{D}}

and,

nM = mass

thus,

V = \frac{\textup{nM}}{\textup{D}}

substituting in the ideal gas relation

we have

P = \frac{\textup{DRT}}{\textup{M}}

or

D = \frac{\textup{PM}}{\textup{RT}}

or

D = \frac{9.87\times44.1}{0.0821\times298}

or

D = 17.8 g/L

Now,

1 gallon = 3.78 Liter

Therefore,

5 gallon = 5 × 3.78 Liter = 18.9 Liter

Thus,

mass of 5 gallon propane = Volume × Density

= 18.9 Liter × 17.8 g/L

= 336.42 g

or

= 0.336 kg

also it is given that Price of 5 gallon propane i.e 0.336 kg = $30

Therefore,

Price per kg = \frac{30}{0.336}

= $89.28

and,

Mass of 5 gallons i.e 18.9 Liter gasoline = Density × Volume

= 0.692 g/cm³ × 18.9 Liter

also,

1 L = 1000 cm³

thus,

= 0.692 g/cm³ × 18.9 × 1000 cm³

= 13078.8 g

or

= 13.078 kg

Therefore,

Price per kg of gasoline = \frac{\$30}{13.078}

= $2.29

hence, propane is more priced than gasoline

4 0
3 years ago
A production department's output for the most recent month consisted of 16,500 units completed and transferred to the next stage
kodGreya [7K]

Answer:

The equivalent units of production for the month, assuming the company uses the weighted average method is 26,400 units.

Explanation:

The equivalent units of production for the month when the company uses the weighted average method is the addition of the units completed and transferred to next stage and degree of completion of the units in ending Work in Process inventory.

This can therefore be calculated as follows:

Equivalent units of production for the month = Units completed and transferred to next stage + Units in ending Work in Process inventory

Since,

Units completed and transferred to next stage = 16,500 units

Units in ending Work in Process inventory = 16,500 * 60% complete = 9,900 units

Therefore, we have:

Equivalent units of production for the month = 16,500 + 9,900 = 26,400 units

Therefore, the equivalent units of production for the month, assuming the company uses the weighted average method is 26,400 units.

3 0
3 years ago
Vaughn Manufacturing purchased office supplies costing $7140 and debited Supplies for the full amount. At the end of the account
Triss [41]

Answer:

A) debit Supplies Expense, $4590; credit Supplies, $4590.

Explanation:

The movements in the supplies account over a period is as a result of purchases ( which results in an increase in the account balance) and usage of supplies( which results in a decrease).

When supplies are purchased, debit supplies account, credit cash. On use of these supplies, debit supplies expense and credit supplies.

Amount of supplies used = $7140 - $2550

=$4,590

Entries required debit Supplies Expense, $4590; credit Supplies, $4590.

3 0
4 years ago
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