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3 years ago

How much of each ingredient is needed to make a 20 L tub of Heavenly Hash ice cream?

Mathematics

1 answer:

ch4aika [34]3 years ago

4 0

It depends on what ingredients you need , and omg i love bts too who’s your bio??

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Suppose we roll a fair six-sided die 20 times and draw ten cards from a standard 52-card deck. Let X be the number of "6"s rolle

Lera25 [3.4K]

Answer:

a) Expected value = 6.406

Variance = 4.905

Standard deviation = 2.45

b) The probability is 0.08547

Step-by-step explanation:

a) Let's suppose that:

X₁ = number of 6´s

X₂ = number of Jack, Queen, King or Aces

The mean of X₁ is:

MeanX₁ = n * p = 20 * (1/6) = 3.33

The variance of X₁ is:

$Var-X_{1} =np(1-p)=3.33(1-(1/6))=2.775$

The mean of X₂ is:

MeanX₂ = 10 * (16/52) = 3.076

The variance of X₂ is:

$Var-X_{2} =3.076(1-(16/52))=2.13$

The expect value of X is:

Xexp = MeanX₁ + MeanX₂ = 3.33 + 3.076 = 6.406

The variance of X is:

VarX = VarX₁ + VarX₂ = 2.775 + 2.13 = 4.905

The standard deviation is:

Xdevi = 4.905/2 = 2.45

b) The probability of drawing at least five six out of 20 rolls is equal to:

∑(1/6)ˣ(5/6)²⁰⁻ˣ = 0.231 with x = 5

The probability of at least 4 Jack, Queen, Kings or Aces is:

∑(16/52)ˣ(1-(16/52))¹⁰⁻ˣ = 0.37 with x = 4

The probability of given event is equal to:

P = 0.231 * 0.37 = 0.08547

5 0

3 years ago

The triangle below what is the sine of 60°

suter [353]

Answer:

Step-by-step explanation:

sin(60) can be simplified into sqrt(3)/2.

3 0

3 years ago

The lifetime, in years, of some electronic component is a continuous random variable with the density f(x) =   k x4 for x ≥ 1

yuradex [85]

I suppose the density is supposed to be

$f(x)=\begin{cases}\frac k{x^4}&\text{for }x\ge1\\0&\text{otherwise}\end{cases}$

(since $kx^4$ diverges as $x\to\infty$ , and 0 is conveniently left out of the domain)

For this to be a proper density function, it must be positive (it is) and its integral over the support $[1,\infty)$ must evaluate to 1. We have

$\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_1^\infty\frac k{x^4}\,\mathrm dx=-\frac k{3x^3}\bigg|_1^\infty=\frac k3=1$

which means $k=3$ .

The distribution function is obtained by integrating the density:

$F(x)=\displaystyle\int_{-\infty}^xf(t)\,\mathrm dt=\begin{cases}0&\text{for }x$

The probability that the component exceeds 2 years in its lifetime is

$P(X>2)=1-P(X\le 2)=1-F(2)=1-\left(1-\dfrac18\right)=\dfrac18$

3 0

3 years ago

HELP PLEASE ASAP !!!

Rom4ik [11]

11.y= 300(12)
12. 300x2= 600=24 m so we need 150 more. well 300/2=150 and 12/2= 6 so 24+6=30 30Gal
13. 30x3.75= $112.50

8 0

3 years ago

carlos provides dog- walking services in his neighborhood. For each walk, he charges a flat fee of $5 for clean-up and $6 per do

dimulka [17.4K]

Let x be the number of dogs. The equation would be

y = 5+6x.

The flat fee is independent of the number of dogs. The $6 per dog fee gets multiplied by the number of dogs.

5 0

3 years ago