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3 years ago

X/-9 is gteater than or equal to 3

Mathematics

1 answer:

Tanzania [10]3 years ago

3 0

x÷-9≥3 then you multiply by -9 so after it will be x≥-27

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Will give brainliest answer!

kifflom [539]

5x + 60y = 35

x +y = 1.5 : rewrite as x = 1.5-y and substitute this formula for x in the first one:

5(1.5-y) + 60y = 35

distribute:

7.5 - 5y + 60y = 35

combine like terms:

7.5 + 55y = 35

subtract 7.5 from both sides:

55y = 27.5

divide both sides by 55 to solve for y

y = 27.5 / 55 = 0.5

now substiute 0.5 for y in the 2nd equation:

x + 0.5 = 1.5

x = 1.5 - 0.5 = 1

he walked for 1 hour

8 0

3 years ago

Please help me with this please help!

Basile [38]

Answersharaddhagupta become my friend

3 0

2 years ago

X:y=5:3 and x+y=56 work ouy the value of x and y

emmainna [20.7K]

Answer:

x=35, y=21

Step-by-step explanation:

A way to rewrite the first equation is $\frac{x}{y} =\frac{5}{3}$

after cross-multiplying, we get 3x=5y.

If we solve for one variable, we can substitute it into the other equation.

Let's solve for x.

3x=5y

x=(5/3)y

Now, we can substitute x=(5/3)y in the equation x+y=56.

(5/3)y+y=56

(8/3)y=56

y=21

Going back to x+y=56, we can now plug back in y, knowing that it is 21.

x+21=56

x=35.

8 0

2 years ago

Sally is standing at one corner of a snowy rectangular field that measures 200 ft by 200 ft. She wishes toreach a warm cabin loc

pshichka [43]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The optimal point(i.e the position of P) that will allow Sally to reach the cabin as quickly as possible is $d = 50 \ ft$ from the cabin.

Step-by-step explanation:

From the question we are told that

The speed from the point Sally is standing to the point P is $u = 3 \ ft /s$

The speed from the point P to the cabin is $v = 5 \ ft /s$

Let denote the distance from the bottom left corner to the P be y ft

Generally according to Pythagoras theorem the distance from Sally's first position to point P is mathematically represented as

$s = \sqrt{y^2 + 200^2}$

Generally the distance from that point P to the cabin is mathematically represented as

$d = 200 -y$

Generally the time it takes Sally to cover that distance s is mathematically represented as

$t_1 = \frac{s}{u}$

=> $t_1 = \frac{ \sqrt{y^2 + 200^2}}{3}$

Generally the time it takes Sally to cover that distance d is mathematically represented as

$t_2 = \frac{d}{v}$

=> $t_2 = \frac{ 200 - y }{5}$

So the total time taken is

$t= \frac{ \sqrt{y^2 + 200^2}}{3} + \frac{ 200 - y }{5}$

Generally the minimum time taken with respect to the distance is mathematically evaluated by differentiating and equating the derivative to 0

$\frac{dt}{dy} =\frac{1}{3} \frac{y}{ \sqrt{y^2 + 200^2} } - \frac{1}{5} =0$

=> $\frac{dt}{dy} = \frac{y^2 }{y^2 + 200 ^2} =\frac{9}{25}$

=> $25y^2 = 9y^2 + 9 * 200^2$

=> $16y^2 = 360000$

=> $y = 150$

So the distance from point P to the cabin is

$d = 200 -150$

=> $d = 50 \ ft$

So the optimal point(i.e the position of P) that will allow Sally to reach the cabin as quickly as possible is $d = 50 \ ft$ from the cabin

8 0

2 years ago

It costs $4 per person. Write an equation where p is people and c is cost.

Softa [21]

The answer is 4p=c because p is for people and person (they both mean the same thing)

4 0

2 years ago