Look at the coordinates. They are both negative. (-5,-1)

Let me plot all the coordinates so you can see:

Joe= (-3,4)

Dan= (1,4)

Roy= (2,-3)

Lee= (-3,-4)

The only person with coordinates that are both negative is Lee.

"C" is the answer. Lee.

I hope this helps!
~kaikers

3 0

4 years ago

Marily ate 320 pounds of vegetables last year. How many ounces did she eat per month? Round to the nearest tenth

8_murik_8 [283]

320 pounds divided by 12 months = around 26.67 pounds per month, if you converted to ounces your answer is 426.67

8 0

3 years ago

Which inequality is equivalent to this one?

Tju [1.3M]

Answer:

D y-8 +2 ≤ -2+2

Step-by-step explanation:

y-8 ≤ -2

Add 2 to each side

y-8 +2 ≤ -2+2

6 0

4 years ago

Read 2 more answers

Two cars are driving towards an intersection from perpendicular directions.

FrozenT [24]

For a better understanding of the solution provided here please find the diagram in the attached file.

In the diagram, A is the intersection. B is the position of the first car and C is the position of the second car. As can be clearly seen, as per the directions given in the question, the cars and the intersection make a right triangle.

The distance between the first car and the intersection is $x$ and the distance between the second car and the intersection is $y$ . The distance between the two cars is depicted by $s$ . As we can see, $s$ is the hypotenuse of the right triangle. At the given instance the distances are 8 meters and 6 meters respectively. Thus, by the Pythagorean Theorem the hypotenuse will be:

$s=\sqrt{8^2+6^2}= \sqrt{100}=10$ ...............(Equation 1)

Now, we know that at any instant the Pythagorean Theorem holds and so we will have, in general:

$s^2=x^2+y^2$

Now, implicitly differentiating the above formula with respect to time, we get:

$2s\frac{ds}{dt}=2x \frac{dx}{dt}+2y \frac{dy}{dt}$

This can be further simplified by dividing both the sides by the common factor 2 as:

$s\frac{ds}{st}=x \frac{dx}{dy}+y\frac{dy}{dt}$ .................(Equation 2)

As we can see from the questions and the diagram, $\frac{dx}{dt}=-2 m/s$ and $\frac{dy}{dt}=-9 m/s$ . The negative sign is there because the distances y and x are reducing as the cars approach the intersection.

Applying this knowledge to (Equation 2) along with the fact that as per (Equation 1), $s=10$ , we get (Equation 2) to become:

$10\times \frac{ds}{dt}=8\times -2+6\times -9=-70$

Therefore, $\frac{ds}{dt}= \frac{-70}{10}=-7 m/s$

Thus, the rate of change of the distance between the cars at the given instant (in meters per second) is $-7$ .

Therefore, out of the given options, option D is the correct one.

4 0

3 years ago