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ValentinkaMS [17]
3 years ago
13

Find the mean absolute deviation of the setback of data. 9, 12, 3, 5, 8

Mathematics
1 answer:
hodyreva [135]3 years ago
7 0

Answer:

3.5

Step-by-step explanation:

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Elementary Algebra Skill
mr_godi [17]

The answer is a = \frac{4}{-3}

Step-by-step explanation:

<em>1. Convert the mixed fraction to an improper fraction</em>

To find the numerator, multiply the denominator by the whole number and add the numerator to it.

The denominator remains the same.

So, 2\frac{2}{3} will be \frac{8}{3}

<em>2. Now the equation is,</em>

\frac{3}{2} a - \frac{4}{3} a = \frac{10}{3} + \frac{8}{3} a

<em>3. Take LCM on both sides. </em>

For the left side, multiply the first fraction by \frac{3}{3} and multiply the second fraction by \frac{2}{2}

\frac{3*3}{2*3} a - \frac{4*3}{3*3} a = \frac{10+8a}{3}

<em>4. Solve by making a the subject</em>

\frac{9a-8a}{6} = \frac{10+8a}{3}

\frac{a}{6} = \frac{10+8a}{3}

\frac{3a}{6} =10+8a

\frac{a}{2} = 10 + 8a

a = 2(10 + 8a)

a = 20 + 16a

a-16a = 20

-15a = 20

a = \frac{20}{-15}

a = \frac{4}{-3}

Therefore, the answer is a = \frac{4}{-3}

Keyword: Equations

Learn more about equations at

  • brainly.com/question/10666510
  • brainly.com/question/4460262
  • brainly.com/question/8955867

#LearnwithBrainly

4 0
3 years ago
How to round to nearest hundredth
loris [4]

Answer:

just look at the decimal after the decimal number is the tenths place the hundreds place and so on if i have to round 567.1092 i would round the nine up to make the zero a one so my rounded answer would be 567.11

Step-by-step explanation:

4 0
3 years ago
Lola used 2 1/2 ink cartridges while her friends used 1 3/4 ink cartridges. How many more ink cartridges did Lola use than her f
iVinArrow [24]

Answer:

Lola used 3/4 more ink cartridges than her friends

Step-by-step explanation:

6 0
3 years ago
What is the value of the function at x=-2​
disa [49]

Answer: i think the correct answer is a

Step-by-step explanation: so if x=-2 then that would mean y=-4 because 2 and 4 r equivalent so it has to be a

3 0
3 years ago
Can you help me solve this radical equation √y-10 = y-2 the sqrt sign is only over the y-10
matrenka [14]
D:y-10\geq0 \wedge y-2\geq0\\&#10;D:y\geq10 \wedge y\geq2\\&#10;D:y\geq10\\\\&#10;\sqrt{y-10}=y-2\\&#10;y-10=(y-2)^2\\&#10;y-10=y^2-4y+4\\&#10;y^2-5y+14=0\\&#10;\Delta=(-5)^2-4\cdot1\cdot14=25-56=-31\\&#10;\Delta
7 0
3 years ago
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