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3 years ago

Find the mean absolute deviation of the setback of data. 9, 12, 3, 5, 8

Mathematics

1 answer:

hodyreva [135]3 years ago

7 0

Answer:

3.5

Step-by-step explanation:

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Elementary Algebra Skill

mr_godi [17]

The answer is a = $\frac{4}{-3}$

Step-by-step explanation:

1. Convert the mixed fraction to an improper fraction

To find the numerator, multiply the denominator by the whole number and add the numerator to it.

The denominator remains the same.

So, 2 $\frac{2}{3}$ will be $\frac{8}{3}$

2. Now the equation is,

$\frac{3}{2}$ a - $\frac{4}{3}$ a = $\frac{10}{3}$ + $\frac{8}{3}$ a

3. Take LCM on both sides.

For the left side, multiply the first fraction by $\frac{3}{3}$ and multiply the second fraction by $\frac{2}{2}$

$\frac{3*3}{2*3}$ a - $\frac{4*3}{3*3}$ a = $\frac{10+8a}{3}$

4. Solve by making a the subject

$\frac{9a-8a}{6}$ = $\frac{10+8a}{3}$

$\frac{a}{6}$ = $\frac{10+8a}{3}$

$\frac{3a}{6}$ =10+8a

$\frac{a}{2}$ = 10 + 8a

a = 2(10 + 8a)

a = 20 + 16a

a-16a = 20

-15a = 20

a = $\frac{20}{-15}$

a = $\frac{4}{-3}$

Therefore, the answer is a = $\frac{4}{-3}$

Keyword: Equations

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4 0

3 years ago

How to round to nearest hundredth

loris [4]

Answer:

just look at the decimal after the decimal number is the tenths place the hundreds place and so on if i have to round 567.1092 i would round the nine up to make the zero a one so my rounded answer would be 567.11

Step-by-step explanation:

4 0

3 years ago

Lola used 2 1/2 ink cartridges while her friends used 1 3/4 ink cartridges. How many more ink cartridges did Lola use than her f

iVinArrow [24]

Answer:

Lola used 3/4 more ink cartridges than her friends

Step-by-step explanation:

6 0

3 years ago

What is the value of the function at x=-2

disa [49]

Answer: i think the correct answer is a

Step-by-step explanation: so if x=-2 then that would mean y=-4 because 2 and 4 r equivalent so it has to be a

3 0

3 years ago

Can you help me solve this radical equation √y-10 = y-2 the sqrt sign is only over the y-10

matrenka [14]

$D:y-10\geq0 \wedge y-2\geq0\\
D:y\geq10 \wedge y\geq2\\
D:y\geq10\\\\
\sqrt{y-10}=y-2\\
y-10=(y-2)^2\\
y-10=y^2-4y+4\\
y^2-5y+14=0\\
\Delta=(-5)^2-4\cdot1\cdot14=25-56=-31\\
\Delta$

7 0

3 years ago