11 units long. When something is rotated it does not change its shape/length, only when it is dilated.
Define the formula for the surface area of a square pyramid.
A square pyramid has a square base and four triangular sides.
The formula for this case is:
A = s ^ 2 + 2 * s * L
Where,
s: side of the base
L: inclined height
The inclined height is:
L = root (h ^ 2 + (s / 2) ^ 2)
Where,
L = root (12 ^ 2 + (12/2) ^ 2)
L = root (144 + 36)
L = root (180)
L = 13.42
Substituting values:
A = (12) ^ 2 + 2 * (12) * (13.42)
A = 466.08 in ^ 2
Answer:
The surface area is:
A = 466.08 in ^ 2
Hi there! The answer is 5/6 hours (which is 50 minutes)
To find the total time Ann spent on her papers, we must add the fractions.

In the first step, we had to make the denominators the same. We need to use the LCM of the numbers 2 and 3. LCM(2,3) = 6.
In the second step we added the fractions. Remember that we only need to add the numerators (the denominator remains the same).
~ Hope this helps you!
Answer:
y=-2/7x+1
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-5-(-1))/(21-7)
m=(-5+1)/14
m=-4/14
simplify
m=-2/7
y-y1=m(x-x1)
y-(-1)=-2/7(x-7)
y+1=-2/7(x-7)
y=-2/7x+2-1
y=-2/7x+1