First, set up your equation.
_(x+4)_ = 7
2
multiply both sides by 2 to cross out the 2 on the bottom
_(x+4)_ *2 = 7*2
2
x+4 =14
subtract 4 from both sides
x+4= 14
-4 -4
x=10
Answer:
Yup!
1) 3/8
2) 3/35
3) 56/99
4) 30/91
5) 32/85
Step-by-step explanation:
Multiply the numerator and denominator across for all of them :O
I will show this for the <u>first</u> one, and all the rest work the same, jut make sure to plug in the right numbers :)
1) ![\frac{3}{4} x \frac{1}{2} = \frac{3x1}{4x2} = \frac{3}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20x%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Cfrac%7B3x1%7D%7B4x2%7D%20%3D%20%5Cfrac%7B3%7D%7B8%7D)
Hope this helps, have a nice day! :D
Answer:
okay. i would say 30% out of 100.
Step-by-step explanation:
Dwight's salary after t year is represented by ![\mathrm{y}=52000\left(1.06^{t}\right)](https://tex.z-dn.net/?f=%5Cmathrm%7By%7D%3D52000%5Cleft%281.06%5E%7Bt%7D%5Cright%29)
<h3><u><em>Solution:</em></u></h3>
Given that
Dwight has a new job that guarantees a six percent raise for each year with the company.
His initial salary is $52,000 per year.
Need to determine equation which models Dwight's salary after t years
Dwight's initial salary = $52,000 per year.
As job guarantees a six percent raise for each year
Dwight's salary after 1 year = 52000 + 6% of 52000 = 52000 + 0.06 x 52000 = 52000 (1.06)
Dwight's salary after 2 year = (52000 x 1.06) + 6 % of (52000 x 1.06)
![\begin{array}{l}{=(52000 \times 1.06)+0.06 \times(52000 \times 1.06)} \\\\ {=(52000 \times 1.06)(1.06)=52000 \times 1.06^{2}}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%3D%2852000%20%5Ctimes%201.06%29%2B0.06%20%5Ctimes%2852000%20%5Ctimes%201.06%29%7D%20%5C%5C%5C%5C%20%7B%3D%2852000%20%5Ctimes%201.06%29%281.06%29%3D52000%20%5Ctimes%201.06%5E%7B2%7D%7D%5Cend%7Barray%7D)
![\begin{array}{l}{\text { Similarly Dwight's salary after } 3 \text { year }=52000 \times 1.06^{3}} \\\\ {\Rightarrow \text { Dwight's salary after } t \text { year }=52000 \times 1.06^{t}}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7B%20Similarly%20Dwight%27s%20salary%20after%20%7D%203%20%5Ctext%20%7B%20year%20%7D%3D52000%20%5Ctimes%201.06%5E%7B3%7D%7D%20%5C%5C%5C%5C%20%7B%5CRightarrow%20%5Ctext%20%7B%20Dwight%27s%20salary%20after%20%7D%20t%20%5Ctext%20%7B%20year%20%7D%3D52000%20%5Ctimes%201.06%5E%7Bt%7D%7D%5Cend%7Barray%7D)
Hence Dwight's salary after t year is represented by = ![52000\left(1.06^{t}\right)](https://tex.z-dn.net/?f=52000%5Cleft%281.06%5E%7Bt%7D%5Cright%29)