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cestrela7 [59]
3 years ago
7

What does 2/5 of 4/5=

Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0

Answer:

\frac{8}{25} which is 0.32 in decimal form

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Options:<br> 14<br> 36<br> 16<br> 12
Lerok [7]

Answer:


12 million dollars.


Step-by-step explanation:


Let the sales in the first year be x million .

So the sales in the second year were x + 4 million, in the third year were 3(x + 4) and this is 48 million dollars.

So we have the equation 3(x + 4) = 48

3x + 12 = 48

3x = 36

x = 12 million dollars.

8 0
3 years ago
Which equations represent the asymptotes of the hyperbola?
makvit [3.9K]

Answer:

  see below

Step-by-step explanation:

The equation of the hyperbola can be written as ...

  ((x -h)/a)² -((y -k)/b)² = 1

This has asymptotes ...

  (x -h)/a ± (y -k)/b = 0

Solving for y, we have ...

  y = ±(b/a)(x -h) +k

Filling in the given values a=6, b=8, h=1, k=2, we have ...

  y = ±8/6(x -1) +2

  y=\dfrac{\pm4x\mp4+6}{3}\\\\\boxed{y=\dfrac{4x+2}{3}\ \text{and }y=\dfrac{10-4x}{3}}

4 0
3 years ago
Math help! 20 Points!
erastova [34]
The anwer is 3 because it 3
4 0
3 years ago
Read 2 more answers
A box contains four 10 nf and eight 100 nf capacitors. (a) what is the probability of obtaining at least two 10 nf capacitors if
grigory [225]

there are 4 of the 10-nf and 8 of the 100-nf capacitors which is a total of 12 items.

the probability of drawing a 10-nf is: 4 out of 12 = \frac{1}{3}

the probability of drawing a 100-nf is: 8 out of 12 =  \frac{2}{3}

(a)  "at least two" means: 2 or 3 or 4

Probability of 2 (10's) and 2 (100's):  \frac{1}{3} x \frac{1}{3} x \frac{2}{3} x \frac{2}{3} = \frac{4}{81}

Probability of 3 (10's) and 1 (100's):  \frac{1}{3} x \frac{1}{3} x \frac{1}{3} x \frac{2}{3} = \frac{2}{81}

Probability of 4 (10's) and 0 (100's):  \frac{1}{3} x \frac{1}{3} x \frac{1}{3} x \frac{1}{3} = \frac{1}{81}

2 or 3 or 4: \frac{4}{81} + \frac{2}{81} + \frac{1}{81} = \frac{7}{81}

(b) without replacement

Probability of 2 (10's) and 2 (100's):  \frac{4}{12} x \frac{3}{11} x \frac{8}{10} x \frac{7}{9} = \frac{4 x 3 x 8 x 7}{12 x 11 x 10 x 9}

Probability of 3 (10's) and 1 (100's):  \frac{4}{12} x \frac{3}{11} x \frac{2}{10} x \frac{8}{9} = \frac{4 x 3 x 2 x 8}{12 x 11 x 10 x 9}

Probability of 4 (10's) and 0 (100's):  \frac{4}{12} x \frac{3}{11} x \frac{2}{10} x \frac{1}{9} = \frac{4 x 3 x 2 x 1}{12 x 11 x 10 x 9}

2 or 3 or 4: \frac{4 x 3 x 8 x 7}{12 x 11 x 10 x 9} + \frac{4 x 3 x 2 x 8}{12 x 11 x 10 x 9} + \frac{4 x 3 x 2 x 1}{12 x 11 x 10 x 9} = \frac{672 + 192 + 24}{12 x 11 x 10 x 9} =  \frac{888}{12 x 11 x 10 x 9}  =  \frac{111}{1485}


8 0
3 years ago
Read 2 more answers
Small sample: During an economic downturn, companies were sampled and asked whether they were planning to increase their workfor
leva [86]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The confidence level interval is  0.016 \le C \le 0.404

Step-by-step explanation:

The sample size is  n =  20

The number planning to increase workforce is  x =  3

 The confidence level is  c  = 98%

The value of proportion for a plus 4 method is

      p = \frac{x+2}{n+4}

substituting values

      p = \frac{3+2}{20+4}

       p =0.21

The z-critical value at confidence level of 98% is

     z_{c}=z_{0.98} =  2.33

This values is obtained from the standard normal table

The confidence level interval can be mathematically represented as

      C =p \ \pm z_{c} * \sqrt{\frac{p(1-p)}{n+4} }

substituting values

      C = 0.21 \pm 2.33 * \sqrt{\frac{0.21(1- 0.21)}{20 +4} }

       C = 0.21 \pm 0.194

=>   0.016 \le C \le 0.404

7 0
3 years ago
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