What does 2/5 of 4/5=

Mathematics

1 answer:

Assoli18 [71]3 years ago

3 0

Answer:

$\frac{8}{25}$ which is 0.32 in decimal form

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lydia graphed triangle LMN at the coordinates L (0, 0), M(2, 2) and N(2, -1). She thinks triangle LMN is a right triangle. Is ly

Karolina [17]

Answer:

she is wrong, LMN is not a right triangle.

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3 years ago

Read 2 more answers

What percent of 137.4 is 96?

Neporo4naja [7]

X = 96

100 137.4

137.4x=(100)(96)

137.4x=9600

137.4x/137.4=9600/137.4

x=70%

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3 years ago

What value of x is in the solution set of 3(x – 4) = 5x + 2?<br> -10

timurjin [86]

Answer:

x = - 7

Step-by-step explanation:

Given

3(x - 4) = 5x + 2 ← distribute left side

3x - 12 = 5x + 2 ( subtract 5x from both sides )

- 2x - 12 = 2 ( add 12 to both sides )

- 2x = 14 ( divide both sides by - 2 )

x = - 7

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3 years ago

3⋅f(−4)−3⋅g(−2)= -27

Reil [10]

Answer:

3⋅f(−4)−3⋅g(−2)= -27 is g = -9/2 +2f

Graph the line using the slope and y-intercept, or two points.

Slope:

6 0

3 years ago

You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

8 0

3 years ago