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Sliva [168]
4 years ago
7

-8(8-3n)-5(n+1)=4n-1-8 I need help on the steps

Mathematics
1 answer:
MrRa [10]4 years ago
5 0
Start by distributing -8 to (8-3n) and -5 to (n+1). The equation becomes:
-64+24n-5n-5=4n-1-8

Next, you can simplify both sides of the equation. It will look like:
-69-19n=4n-9

Next, add 19n to both sides so you isolate the variable on one side of the equation. You will get:
-69=23n-9

Now, you can proceed to solve this like any other two-step equation. Add 9 to both sides:
-78=23n
Divide both sides by 23:
-3.3913=n

Hope this helps!
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4 years ago
HELP PLEASE WILL MARK BRAINLIEST!!
Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

from \: the \: figure \\ AB = 300 \: ft \:  \:  \: angle \: C = 60  \:( theta)\: degress \\ in \: triangle \: ABC \: using \:  tan \: theta\\  \tan(60)  =  \frac{opposite \: side}{adjacent \: side}  \\  \tan(60)  =  \frac{300}{BC}  \\  \sqrt{3}  =  \frac{300}{BC}  \\ BC =  \frac{300}{ \sqrt{3} }  \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\   \tan(30 )  =\frac{opposite \: side}{adjacent \: side} \\  \tan(30)   =  \frac{300}{BD}  \\  \frac{1}{ \sqrt{ 3} }  =  \frac{300}{BD}  \\ BD = 300 \sqrt{3}  \\ CD = BD - BC \\  = 300 \sqrt{3 }  - 100 \sqrt{3}  \\  = (300 - 100) \sqrt{3}  \\  = 200 \sqrt{3 }  \\  = 200 \times 1.732 \\  = 346.4 \: ft

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

7 0
4 years ago
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