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3 years ago

6

Which term describes the maintenance of a steady internal state in the body?

1 answer:

Sonja [21]3 years ago

5 0

B, homeostasis. “Homeostasis is the state of steady internal, physical, and chemical conditions maintained by living systems.”

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Changes in DNA are known as mutations and can be sometimes produce beneficial changes in population. A mutant form of the normal

soldier1979 [14.2K]

The dark colored moths are beneficial in a polluted area because they have a lesser chance of being eaten since they blend into the trees polluted with soot.

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3 years ago

Does the air in a room or water in a pot have to be at certain temperature to create convection? Yes or no? and explain why?

MA_775_DIABLO [31]

Answer:

Yes. There must be a difference.

Explanation:

The part of water with low density (warm or hot) would rise, and the cold water would sink. This creates a convection.

5 0

3 years ago

Fructose-1-P is hydrolyzed according to: Fructose-1-P + H2O → Fructose + Pi If a 0.2 M aqueous solution of Froctose-1-P is allow

aalyn [17]

Answer:

$\Delta G^{\circ}=-15902 J/mol$

Explanation:

In this problem we only have information of the equilibrium, so we need to find a expression of the free energy in function of the constant of equilireium (Keq):

$\Delta G^{\circ}=-R*T*ln(K_{eq})$

Being Keq:

$K_{eq}=\frac{[fructose][Pi]}{[Fructose-1-P]}$

Initial conditions:

$[Fructose-1-P]=0.2M$

$[Fructose]=0M$

$[Pi]=0M$

Equilibrium conditions:

$[Fructose-1-P]=6.52*10^{-5}M$

$[Fructose]=0.2M-6.52*10^{-5}M$

$[Pi]=0.2M-6.52*10^{-5}M$

$K_{eq}=\frac{(0.2M-6.52*10^{-5}M)*(0.2M-6.52*10^{-5}M)}{6.52*10^{-5}M}$

$K_{eq}=613.1$

Free-energy for T=298K (standard):

$\Delta G^{\circ}=-8.314\frac{J}{mol*K}*298K*ln(613.1)$

$\Delta G^{\circ}=-15902 J/mol$

3 0

3 years ago

If 4.50 g of methane gas (CH4) is in a 2.00-L container at 35°C, what is the pressure in the

Airida [17]

Answer:

The answer to your question is Pressure = 3.55 atm

Explanation:

Data

R = 0.082 atm L/mol°K

mass = 4.5 g

volume = 2 L

temperature = 35°C

Pressure = ?

Process

1.- Calculate the moles of Methane

molar weight = 12 + 4 = 16 g

16 g of Methane --------------- 1 mol

4.5 g --------------- x

x = (4.5 x 1)/16

x = 0.281 moles

2.- Convert temperature to Kelvin

°K = 273 + 35

= 308

3.- Use the ideal gas law to solve this problem

PV = nRT

- Solve for P

P = nRT / V

- Substitution

P = (0.281)(0.082)(308) / 2

- Simplification

P = 7.097 / 2

- Result

P = 3.55 atm

4 0

3 years ago

Read 2 more answers

Beta-galactosidase follows Michaelis-Menten kinetics. A 5 micromolar solution of beta-galactosidase catalyzes the formation of 0

jek_recluse [69]

Answer : The beta-galactosidase's $K_{cat}$ is, $160s^{-1}$

Explanation :

Michaelis-Menten formula used :

$V_o=\frac{V_{max}}{K_{cat}}$

where,

$V_o$ = initial concentration = $5\mu mol=5\times 10^{-6}mol$

$V_{max}$ = maximum concentration = $0.8mmol.s^{-1}=0.8\times 10^{-3}mol.s^{-1}$

$K_{cat}$ = Michaelis-Menten constant = ?

Now put all the given values in the above formula, we get:

$5\times 10^{-6}mol=\frac{0.8\times 10^{-3}mol.s^{-1}}{K_{cat}}$

$K_{cat}=160s^{-1}$

Therefore, the beta-galactosidase's $K_{cat}$ is, $160s^{-1}$

6 0

3 years ago