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mote1985 [20]
3 years ago
7

Solve the following equation using distribution.

Mathematics
2 answers:
AleksandrR [38]3 years ago
7 0

Answer:

answer is 5.5 on edgen

Step-by-step explanation:

I just solved the problem

sergey [27]3 years ago
5 0

Answer:

The top answer is correct :)

Step-by-step explanation:

I took the test

Have a great day!!

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What is the completely factored form of f(x) = 6x3 – 13x2 – 4x + 15?
masya89 [10]

We have to determine the complete factored form of the given polynomial

f(x)=6x^3-13x^2-4x+15.

Let x= -1 in the given polynomial.

So, f(-1)= 6(-1)^3-13(-1)^2-4(-1)+15 = -6-13+4+15 = 0

So, by factor theorem

(x+1) is a factor of the given polynomial.

So, dividing the given polynomial by (x+1), we get quotient as 6x^2-19x+15.

So, 6x^3-13x^2-4x+15 = (x+1)6x^2-19x+15.

= (x+1)(6x^2-10x-9x+15)

=(x+1)[ 2x(3x-5)-3(3x-5)]

= (x+1)(2x-3)(3x-5) is the completely factored form of the given polynomial.

Option D is the correct answer.

5 0
3 years ago
Read 2 more answers
Please help me asap​
omeli [17]

Answer:

-.51, .1/2, .42, 11/20

3 0
3 years ago
Read 2 more answers
The function f is defined by f(x) = x^2 + 3x -10 , if f(x + 5) = x^2 + kx + 30, k=
boyakko [2]

Answer:

k = 13

Step-by-step explanation:

substitute x = x + 5 into f(x) , that is

f(x + 5) = (x + 5)² + 3(x + 5) - 10 ← expand squared factor using FOIL

          = x² + 10x + 25 + 3x + 15 - 10

         = x² + 13x + 30

compare this with f(x + 5) = x² + kx + 30

for the 2 expressions to be equal , then k = 13

6 0
2 years ago
Find the GCF of 6x+4 and divide
ella [17]
The GCF is 2
Merry Christmas
4 0
3 years ago
You randomly choose one of the morales.Without replacing the first marble, you choose a second marble. What is the probability o
IrinaK [193]
Let’s say, hypothetically speaking, you chose the second marble without replacing the first marble so, events are hypothetically dependent. Events are dependent if the occurrence of one hypothetical event hypothetically does affect the likelihood that the other events occur. The probably of two or more dependent events A and B is the probability of A times the probability of B after A hypothetically occurs

P(A and B) = P(A) x P(B after A)

Choose the first marble

The total number of hypothetical marbles are, hypothetically speaking, 4 on a hypothetical basis, and there is one red marble.

P(red)=1/4

Choose the second marble

Without hypothetically replacing the hypothetical first marble, you choose the hypothetical marble, hypothetically speaking. So, the total hypothetical number of marbles are, hypothetically, 3, and there is, hypothetically, one green marble.

P(green) = 1/3

The probability of choosing red and then, hypothetically, green is:

P(red and green) = P(red) x P(green)
=1/4 x 1/3

= 1/12

P(red and green) is hypothetically equal to 1/12 on a hypothetical account.

Final hypothetical answer: 1/12
4 0
2 years ago
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