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tensa zangetsu [6.8K]
3 years ago
15

ΔRST and ΔXYZ are equilateral triangles. The ratio of the perimeter of ΔRST to the perimeter of ΔXYZ is 1 to 3. The area of ΔRST

is 10.825 square inches. What is the area of ΔXYZ? (round to nearest tenth)
Mathematics
2 answers:
Nataliya [291]3 years ago
8 0
For the scale factor of 1:3. Use ratio and proportion to solve for the area of the triangle. 

area of triangle RST/ area of triangle XYZ = (1/3)^2
where
area of traianlge RST = 10.825 inch^2
Area of triangle XYZ= Area of triangle RST x (3)^2
Substitute the given values=97.4 inch^2



Marysya12 [62]3 years ago
6 0

I worked it out and checked to get D- 97.4 :)

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Question 12 (2 points)
elena55 [62]

Answer:

A box plot is drawn with end points at 24 and 49.The box extends from 28 to 44 and a vertical line is drawn inside the box at 34.

Step-by-step explanation:

Ordering the data given :

24,28,32,34,40,44,49

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Minimum = 24

Maximum = 49

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Lower quartile, Q1 = 1/4(n+1)th term

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3 0
3 years ago
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nignag [31]

Answer:

D

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Using the Cosine rule to find AC

AC² = BC² + AB² - (2 × BC × AB × cosB )

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      = 324 + 144 - 432cos75°

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      = 356.2 ( take the square root of both sides )

AC = \sqrt{356.2} ≈ 18.9

-----------------------------------------

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∠ A = sin^{-1} ( \frac{18sin75}{18.9} ) ≈ 66.9°

4 0
3 years ago
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