All categories

3 years ago

10.Give the possible values for the magnetic quantum number for each of the following orbitals (a) 4p: (b) 3d: (c) 2s (d) 5P

Chemistry

1 answer:

andre [41]3 years ago

5 0

Answer:

(a) 4p: ml = -3, -2, -1, 0, +1, +2, +3

(b) 3d: ml = -2, -1, 0, +1, +2

(c) 2s: ml = -1, 0, +1

(d) 5p: ml = -4, -3, -2, -1, 0, +1, +2, +3, +4

Explanation:

Manetic quantum numbers determine the spatial orientation and number of orbitals in the subshell. ml is from -l to +l.

You might be interested in

In a five-fold serial dilution of a 20 ug/mL solution, all tube dilutions are 1/5. What is the substance concentration in the th

sergij07 [2.7K]

Answer:

In the third tube, the concentration is 0.16 ug/mL

Explanation:

In the first step, the solution is diluted by 5. Then, the concentration will be

20 ug/mL / 5 = 4 ug/mL

Then, in the second step this 4 ug / ml solution is diluted by a factor of five again:

4 ug /ml / 5 = 0.8 ug/mL

This solution is then diluted again by 5 and the concentration in the third tube will be then:

0.8 ug/mL / 5 = <u>0.16 ug/mL </u>

<u />

Another way to calculate this is to divide the original concentration by the dilution factor ( 5 in this case) elevated to the number of dilutions. In this case:

Concentration in the third tube = 20 ug/mL / 5³ = 0.16 ug/mL

3 0

3 years ago

When does the dipole arrow point to Atom A? (Use electronegativity in your explanation)

Marrrta [24]

Answer:

Dipole, less electronegativity, higher electronegativity

8 0

3 years ago

NEED HELP ASAFP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!PLEASE!

sp2606 [1]

Here to help! What’s up?

6 0

4 years ago

An elephant has a mass of 4000 kg goes to the moon to participate in the Elephant

expeople1 [14]

Answer:

Ano daw

Explanation:

Di ko alam sagot eh

5 0

3 years ago

A gaseous mixture at 265K and 1.0 atm contains 25 O2 60 N2 and 15 CO2 mole basis The velocities of the components are 0.084 cm s

Free_Kalibri [48]

Answer:

The molar average velocity is 0.0588 cm/s

The N₂ diffusion velocity relative to the mole average velocity is -0.1428 cm/s

The molar diffusional flux of N₂ is -3.9x10⁻³

Explanation:

Given data:

T = temperature = 265 K

O₂ = 25%

N₂ = 60%

CO₂ = 15%

vO₂ = -0.084 cm/s

vN₂ = 0.12 cm/s

vCO₂ = 0.052 cm/s

The molar average velocity is equal:

$v_{av} =(0.25*(-0.084))+(0.6*0.12)+(0.15*0.052)=0.0588cm/s$

The N₂ diffusion velocity relative to the molar average velocity is:

$v_{i} -v_{av} =-0.084-0.0588=-0.1428cm/s$

The molar diffusional flux of N₂ is:

$N_{N_{2} } =\frac{P}{RT} y_{A} (v_{i} -v_{av} )=-3.9x10^{-3}$

8 0

4 years ago