Question

terry runs a snowplowing business. Income from snowplowing is given by the function f(x)=35.5x+6 , where f(x) is the income in dollars and x is the snowfall in inches received during a winter. if during the years 2006 to 2011. Terry's town received 53,42,55,63,58, and 47 inches of snowfall, what was his income (in dollars) during those years?

Answer 1

Answer: The total income during those years is $11325.

Step-by-step explanation:

Since we have given that

Income from snowplowing is given by

$f(x)=35.5x+6,\\\\\text{where x is the snowfall in inches received during a winter}$

if Amount of snow received in 2006 = 53

Income  is given by

$f(x)=35.5x+6\\\\f(53)=35.5\times 53+6\\\\f(53)=1887.5$

Amount of snowfall received in 2007 = 42

Income is given by

$f(x)=35.5x+6\\\\f(42)=35.5\times 42+6\\\\f(42)=\ 1497$

Amount of snowfall received in 2008 = 55

Income is given by

$f(x)=35.5x+6\\\\f(55)=35.5\times 55+6\\\\f(55)=\ 1958.5$

Amount of snowfall received in 2009 = 63

Income is given by

$f(x)=35.5x+6\\\\f(63)=35.5\times 63+6\\\\f(63)=\ 2242.5$

Amount of snowfall received in 2010 = 58

Income is given by

$f(x)=35.5x+6\\\\f(58)=35.5\times 58+6\\\\f(58)=\42065$

Amount of snowfall received in 2011 = 47

Income is given by

$f(x)=35.5x+6\\\\f(47)=35.5\times 47+6\\\\f(47)=\ 1674.5$

So, Total income during those years is given by

$1887.5+1497+1958.5+2242.5+2065+1674.5\\\\=\ 11325$

Hence, the total income during those years is $11325.

Answer 2

First year- $1,887.5
second year- $1,497
third year- $1,958.5
fourth year- $2,242.5
fifth year- $2,065
sixth year- $1,674.5

And if you needed it to be added together, for the total income over those six years, its $7,479