Answer:
I think its 3 combos
Step-by-step explanation:
9÷3=3 combos?
Hope this helps :D
Answer:
GCF OF 20 AND 32: 4
Gcf of 45 and 75: 15
Step-by-step explanation:
GcF of 20 and 32
Factors of 20: 1, 2, 4, 5, 10, 20
Factors of 32: 1, 2, 4, 8, 16, 32
COMMON FACTORS: 1, 2, 4
GCF:4
Gcf of 45 and 75
Factors of 45: 15, 9, 5, 3, 1.
Factors of 75: 25, 15, 5, 3, 1.
CommoN factors: 1, 3, 5, 15
GCF:15
HOPE OT HELPED
Answer:
50h+6
Step-by-step explanation:
50h+ (150/25) <--- Divide/ simplify
=50h+6
Answer:
ΔGJH ≅ ΔEKF
HL: GH and EF
SAS: FK and JH (or GH and EF)
ASA: ∠JGH and ∠FEK (or ∠EFK and ∠JHG)
ΔGFJ ≅ ΔEKH
SSS: KH and FJ
SAS: ∠KEH and ∠FGJ
Step-by-step explanation:
List whatever angles/sides need to be congruent for the two triangles to be congruent.
Prove ΔGJH ≅ ΔEKF using....
- HL (Hypotenuse + Leg)
We already have two legs that are congruent (EK and GJ), so we just need the hypotenuses (GH and EF) to be equal.
- SAS (Side + Angle + Side)
1 pair of sides (EK and JG) are equal, and m∠EKF = m∠GJH. So we need one more side. You can either use FK and JH or GH and EF.
- ASA (Angle + Side + Angle)
1 pair of angles (∠EKF and ∠GJH) are already given as equal, and 1 pair of sides (EK and GJ) are equal. We just need one more pair of angles. So either ∠JGH and ∠FEK or ∠EFK and ∠JHG.
Prove ΔGFJ ≅ ΔEKH using...
- SSS (Side + Side + Side)
Two pairs of sides (EK + GJ and EH + FG) are equal, so KH and FJ need to be equal.
- SAS (Side + Angle + Side)
FG + EH and KE + GJ are equal. We need to use the angle in between them to use SAS, so ∠KEH and ∠FGJ need to be equal.
