What is the equation of the vertical asymptote of the graph of f(x) = 2 log3(x + 1) – 3?

Mathematics

1 answer:

hammer [34]3 years ago

4 0

Set the argument (x+1) equal to zero.
$x + 1 = 0 \\ x = - 1$

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ra1l [238]

Answer:its B or A

Step-by-step explanation:i guess so

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rjkz [21]

The test statistic and p-value of the given data are 6.274 and 0.0001 respectively.

<h3>Test Statistic</h3>

The test statistic can be calculated using the formula below

$t = \frac{x-\mu}{\sigma / \sqrt{n} }$

Solving for the mean and standard deviation, we can substitute the values into the above equation which will be

$t = \frac{x-\mu}{\sigma / \sqrt{n} } = 6.274$

<h3>P-Value</h3>

Using the data from the test statistic, we can calculate the p-value of the data

$p-value = p(z < 6.274)= 0.0001 = 0.00$

From the calculation above, the test statistic and p-value of the given data are

6.274
0.0001

Learn more on test statistic and p-value here;

brainly.com/question/4621112

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1 year ago

Help please? 15 points here

MakcuM [25]

Answer:

64°

Step-by-step explanation:

In circle with center P, AD is diameter.

$\therefore m\angle DPE + m\angle APE = 180\degree \\\therefore (33k-9)\degree + 90\degree = 180\degree \\\therefore (33k-9)\degree = 180\degree -90\degree \\\therefore (33k-9)\degree = 90\degree \\\therefore 33k-9 = 90\\\therefore 33k= 90+9\\\therefore 33k= 99\\\therefore k= \frac{99}{33}\\\therefore k=3\\ m\angle CPD = (20k +4)\degree \\\therefore m\angle CPD = (20\times 3 +4)\degree \\\therefore m\angle CPD =(60+4)\degree \\\therefore m\angle CPD =64\degree \\m\overset {\frown}{CD} = m\angle CPD\\\therefore m\overset {\frown}{CD} = 64\degree$