The correct answer are
identify the positive ion and charge
balance the charges
identify the negative ion and charge
The correct option would be 3.
Only thermal energy changes
Hope this helps you
Brainliest would be appreciated
-AaronWiseIsBae
Explanation:
A post-test or a mastery test can be unlocked if the learner who has the of it previously can complete the given tutorial with the test.
After the tutorial with the test, the learner will have to complete everything and if he passes the test with a completed answer then he will see that the Mastery Test has been unlocked. Also after the mastery test is unlocked it can be done again.
Answer: Balanced molecular equation :
![2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)](https://tex.z-dn.net/?f=2Na_3PO_4%28aq%29%2B3%28CH_3COO%29_2Zn%28aq%29%5Crightarrow%206CH_3COONa%28aq%29%2BZn_3%28PO_4%29_2%28s%29)
Total ionic equation:
The net ionic equation:
![2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)](https://tex.z-dn.net/?f=2PO_4%5E%7B3-%7D%28aq%29%2B3Zn%5E%7B2%2B%7D%28aq%29%5Crightarrow%20Zn_3%28PO_4%29_2%28s%29)
Explanation:
Complete ionic equation : In complete ionic equation, all the substances that are strong electrolyte are present in an aqueous state as ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
When sodium phosphate and zinc acetate then it gives zinc phosphate and sodium acetate as product.
The balanced molecular equation will be,
![2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)](https://tex.z-dn.net/?f=2Na_3PO_4%28aq%29%2B3%28CH_3COO%29_2Zn%28aq%29%5Crightarrow%206CH_3COONa%28aq%29%2BZn_3%28PO_4%29_2%28s%29)
The total ionic equation in separated aqueous solution will be,
![6Na^+(aq)+2PO_4^{3-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)](https://tex.z-dn.net/?f=6Na%5E%2B%28aq%29%2B2PO_4%5E%7B3-%7D%28aq%29%2B6CH_3COO%5E-%28aq%29%2B3Zn%5E%7B2%2B%7D%28aq%29%5Crightarrow%206CH_3COO%5E-%28aq%29%2B6Na%5E%2B%28aq%29%2BZn_3%28PO_4%29_2%28s%29)
In this equation, and are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
![2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)](https://tex.z-dn.net/?f=2PO_4%5E%7B3-%7D%28aq%29%2B3Zn%5E%7B2%2B%7D%28aq%29%5Crightarrow%20Zn_3%28PO_4%29_2%28s%29)
Answer:
The chemistry of iron is dominated by the +2 and +3 oxidation states i.e. iron(II) and iron(III) complexes e.g. Fe2+ and Fe3+ complex ions with selected ligands, usually of an octahedral shape, a few tetrahedral iron(III) complexes are mentioned too. The reactions of the aqueous ions iron(II) and iron(III) with ammonia, sodium hydroxide and sodium carbonate are described and explained as are complexes of iron(III) with the chloride ion and cyanide ion.
principal oxidation states of iron, redox reactions of iron, ligand substitution displacement reactions of iron, balanced equations of iron chemistry, formula of iron complex ions, shapes colours of iron complexes, formula of compoundsExplanation: