Answer:
Percentage = 40%
Explanation:
Given data:
Mass of SO₄ = 2.00 g
Mass of BaSO₄ = 5.00 g
Percentage of SO₄ = ?
Solution:
Percentage of any substance can be calculated by following formula.
Percentage = given amount / total amount × 100
Now we will calculate the percentage of SO₄.
Percentage = 2.00 g / 5.00 × 100
Percentage = 0.4 × 100
Percentage = 40%
I believe this method of problem solving would be categorized as unit or dimensional analysis.
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Answer:
57.4 g/mol
Explanation:
Step 1: Convert 450 cm³ to L
We will use the conversion factors 1 cm³ = 1 mL and 1000 mL = 1 L.
450 cm³ × 1 mL/1 cm³ × 1 L/1 mL = 0.450 L
Step 2: Convert 23 °C to Kelvin
We will use the following expression.
K = °C + 273.15 = 23 + 273.15 = 296 K
Step 3: Calculate the number of moles of the gas
We will use the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 700 mmHg × 0.450 L / (62.4 mmHg.L/mol.K) × 296 K = 0.0171 mol
Step 4: Calculate the molar mass of the gas
0.982 g of the gas correspond to 0.0171 moles.
M = 0.982 g/0.0171 mol = 57.4 g/mol
Answer:
50.3mL of mercury are in 1.50lb
Explanation:
Punds are an unit of mass. To convert mass to volume we must use density (13.546g/mL). Now, As you can see, density is in grams but the mass of mercury is in pounds. That means we need first, to convert pounds to grams to use density and obtain volume of mercury.
<em>Mass mercury in grams:</em>
1.50lb * (1kg / 2.20lb) = 0.682kg = 682g of mercury.
<em>Volume of mercury:</em>
682g Mercury * (1mL / 13.546g) =
<h3>50.3mL of mercury are in 1.50lb</h3>